Equations balanced on the previous day |
H3PO4 + 3 MH3 = (MH4)3PO4
Sr(NO3)2 + Na2C2O4 = SrC2O4 + NaNO3 =>
Sr(NO3)2 + Na2C2O4 = SrC2O4 + 2 NaNO3
Al(OH)3 + H2SO4 = Al2(SO4)3 + H2O =>
2 Al(OH)3 + 3 H2SO4 = Al2(SO4)3 + 6 H2O
C2952H4664O832N812S8Fe4 + O2 = CO2 + H2O + NH3 + S + Fe =>
C2952H4664O832N812S8Fe4 + 3093 O2 = 2952 CO2 + 1114 H2O + 812 NH3 + 8 S + 4 Fe
BaO2 + AgNO3 = Ag + O2 + Ba(NO3)2 =>
BaO2 + 2 AgNO3 = 2 Ag + O2 + Ba(NO3)2
Mg + AuCl = Au + MgCl2 =>
Mg + 2 AuCl = 2 Au + MgCl2
(Cr(N2CO)6)4(Cr(CN)6)3 + KMnO4 + H2SO4 = K2Cr2O7 + MnSO4 + CO2 + KNO3 + K2SO4 + H2O =>
10(Cr(N2CO)6)4(Cr(CN)6)3 + 984 KMnO4 + 1111 H2SO4 = 35 K2Cr2O7 + 984 MnSO4 + 420 CO2 + 660 KNO3 + 127 K2SO4 + 1111 H2O
KHCO3 + H2O2 = K2C2O6 + H2O =>
2 KHCO3 + H2O2 = K2C2O6 + 2 H2O
H3PO4 + MH3 = (MH4)3PO4 =>
H3PO4 + 3 MH3 = (MH4)3PO4
FeSO4 + HCl = Fe + H2SO4 + Cl2 =>
FeSO4 + 2 HCl = Fe + H2SO4 + Cl2
C2H6O(l) + O2(g) = H2O(g) + CO2(g) =>
C2H6O(l) + 3 O2(g) = 3 H2O(g) + 2 CO2(g)
S{2-} + SO3{2-} + H{+} = S2O3{2-} + H2O =>
2 S{2-} + 4 SO3{2-} + 6 H{+} = 3 S2O3{2-} + 3 H2O
CoC2O4*2H2O + O2 = CoO + H2O + CO2 =>
2 CoC2O4*2H2O + O2 = 2 CoO + 4 H2O + 4 CO2
H2SO4 + CO2 = H2CO3 + SO3 =>
H2SO4 + CO2 = H2CO3 + SO3
C6H5OH = C6H5O + H2 =>
2 C6H5OH = 2 C6H5O + H2
HClO + PO10 = HPO4 + ClO7 =>
HClO + PO10 = HPO4 + ClO7
Pb(N3)2(aq) + NaCl(aq) = NaN3(s) + PbCl2(aq) =>
Pb(N3)2(aq) + 2 NaCl(aq) = 2 NaN3(s) + PbCl2(aq)
N2O + KMnO4 + H2SO4 = MnSO4 + Mn(NO3)2 + K2SO4 + H2O =>
5 N2O + 8 KMnO4 + 7 H2SO4 = 3 MnSO4 + 5 Mn(NO3)2 + 4 K2SO4 + 7 H2O
(NH4)Cl = NH3 + HCl =>
(NH4)Cl = NH3 + HCl
As2O3 + Al + HCl = AsH3 + AlCl3 + H2O =>
As2O3 + 4 Al + 12 HCl = 2 AsH3 + 4 AlCl3 + 3 H2O
KBrO3 + SO2 + H2O = KBr + H2SO4 =>
KBrO3 + 3 SO2 + 3 H2O = KBr + 3 H2SO4
Ca(NO2)2 + NaI = CaI2 + NaNO2 =>
Ca(NO2)2 + 2 NaI = CaI2 + 2 NaNO2
Cu(SO4) + K(NO3) = Cu(NO3) + K(SO4) =>
Cu(SO4) + K(NO3) = Cu(NO3) + K(SO4)
H2S + K2Cr2O7 + HCl = CrCl3 + S8 + KCl + H2O =>
24 H2S + 8 K2Cr2O7 + 64 HCl = 16 CrCl3 + 3 S8 + 16 KCl + 56 H2O
NH4Cl = H2 + NCl =>
NH4Cl = 2 H2 + NCl
NH4Cl + NaOH = NH3 + H2O + NaCl = =>
NH4Cl + NaOH = NH3 + H2O + NaCl
Ca(NO3)2*4H2O + (NH4)10H2(W2O7)6 + NH2CONH2 = CaWO4 + CO2 + H2O + N2 =>
12 Ca(NO3)2*4H2O + (NH4)10H2(W2O7)6 + 15 NH2CONH2 = 12 CaWO4 + 15 CO2 + 99 H2O + 32 N2
Fe(NH4)2(SO4)2*6H2O + H2C2O4 = FeC2O4*2H2O + NH4HSO4 + H2O =>
Fe(NH4)2(SO4)2*6H2O + H2C2O4 = FeC2O4*2H2O + 2 NH4HSO4 + 4 H2O
CH3COOH + HCN = CH3COOCN + H =>
CH3COOH + HCN = CH3COOCN + 2 H
H2SO4 + K(HCO3)2 = KSO4 + H2O + CO2 =>
H2SO4 + K(HCO3)2 = KSO4 + 2 H2O + 2 CO2
AlCl3(aq) + H2O(l) = Al(OH)3 + HCl =>
AlCl3(aq) + 3 H2O(l) = Al(OH)3 + 3 HCl
Mn + OH = Mn(OH)2 =>
Mn + 2 OH = Mn(OH)2
C6H5ONa + HCOOH = C6H5OH + HCOONa =>
C6H5ONa + HCOOH = C6H5OH + HCOONa
NH3 + F = N2F4 + H2 =>
2 NH3 + 4 F = N2F4 + 3 H2
NaCO3 + CoNO3 = CoCO3 + NaNO3 =>
NaCO3 + CoNO3 = CoCO3 + NaNO3
CH3HCOHCH2CH(CH3)2 + [Ag(NH3)2]{+} + OH{-}{+} = Ag + CH3COO + NH3 + H2O =>
CH3HCOHCH2CH(CH3)2 + 15[Ag(NH3)2]{+} + 15 OH{-}{+} = 15 Ag + 3 CH3COO + 30 NH3 + 10 H2O
Pb(CH3COO)2 + HCl = PbCl2(s) + CH3COOH =>
Pb(CH3COO)2 + 2 HCl = PbCl2(s) + 2 CH3COOH
Al2(SO4)3 + NH4OH + H2SO4 + H2O = NH4Al(SO4)2*12H2O =>
Al2(SO4)3 + 2 NH4OH + H2SO4 + 22 H2O = 2 NH4Al(SO4)2*12H2O
Ag3PO4 + H3PO4 = AgH2PO4 =>
Ag3PO4 + 2 H3PO4 = 3 AgH2PO4
CO2 + SO3 = CO2SO3 =>
CO2 + SO3 = CO2SO3
MgSO4 + KF = K2SO4 + MgF2 =>
MgSO4 + 2 KF = K2SO4 + MgF2
H2SO4 + Fe = Fe(SO3)3 + H2O =>
3 H2SO4 + Fe = Fe(SO3)3 + 3 H2O
Cu(NO3)2 + HCOONa = Cu(HCOO)2 + NaNO3 =>
Cu(NO3)2 + 2 HCOONa = Cu(HCOO)2 + 2 NaNO3
H3PO4 + MH3 = (MH4)3PO4 =>
H3PO4 + 3 MH3 = (MH4)3PO4
Pb(NO3)2 + KCN = Pb + KCN(NO3) =>
Pb(NO3)2 + 2 KCN = Pb + 2 KCN(NO3)
CU(OH)2 + CO2 = CUCO3 + H2O =>
CU(OH)2 + CO2 = CUCO3 + H2O
MgO(g) + HCl(l) = MgCl2(aq) + H2O(l) =>
MgO(g) + 2 HCl(l) = MgCl2(aq) + H2O(l)
HClO4(aq) + H2O(l) = H3O + HClO5 =>
HClO4(aq) + 3 H2O(l) = 2 H3O + HClO5
CH3CH2CH2COCH3 + H2 = C5H12O =>
CH3CH2CH2COCH3 + H2 = C5H12O
C + H2 + O2 = C20H30O =>
40 C + 30 H2 + O2 = 2 C20H30O
Balance the equation of any chemical reaction
Equations balanced on the previous day |
Equations balanced on 12/23/24
Equations balanced on 01/22/24
Please let us know how we can improve this web app.