| Equations balanced on the previous day |
3 O2(g) = 2 O3(g)
Li + Ba(NO3)2 = Ba + Li(NO3)2 =>
Li + Ba(NO3)2 = Ba + Li(NO3)2
U3O8 = U + O2 =>
U3O8 = 3 U + 4 O2
Fe + Br2 = FeBr3 =>
2 Fe + 3 Br2 = 2 FeBr3
FeSO4 + HBrO + HCl = FeCl3 + FeBr3 + Fe2(SO4)3 + H2O =>
6 FeSO4 + 3 HBrO + 3 HCl = FeCl3 + FeBr3 + 2 Fe2(SO4)3 + 3 H2O
Ba(NO3)2 + Na2(CrO4) = BaCrO4 + Na(NO3) =>
Ba(NO3)2 + Na2(CrO4) = BaCrO4 + 2 Na(NO3)
C5H8(g) + O2(g) = CO2(g) + H2O(g) =>
C5H8(g) + 7 O2(g) = 5 CO2(g) + 4 H2O(g)
Na2SO4(aq) + SrCl2(aq) = NaCl(aq) + SrSO4(s) =>
Na2SO4(aq) + SrCl2(aq) = 2 NaCl(aq) + SrSO4(s)
C2H6O + NaMnO4 = MnO2 + NaOH + C2H3O2Na + H2O =>
3 C2H6O + 4 NaMnO4 = 4 MnO2 + NaOH + 3 C2H3O2Na + 4 H2O
O2(g) + SO2(g) + NaCl(s) = Na2SO4(s) + Cl2(g) =>
O2(g) + SO2(g) + 2 NaCl(s) = Na2SO4(s) + Cl2(g)
KCN + HCl = HCN(g) + KCl =>
KCN + HCl = HCN(g) + KCl
Na2SO4(aq) + SrCl2(aq) = NaCl + SrSO4 =>
Na2SO4(aq) + SrCl2(aq) = 2 NaCl + SrSO4
Li + Ba(NO3)2 = Ba + Li(NO3) =>
2 Li + Ba(NO3)2 = Ba + 2 Li(NO3)
I3 + KCl = Cl2 + KI =>
2 I3 + 6 KCl = 3 Cl2 + 6 KI
RbOH + BaBr2 = Ba(OH)2 + RbBr =>
2 RbOH + BaBr2 = Ba(OH)2 + 2 RbBr
CoCl2 + Na2HPO4 = CoHPO4 + NaCl =>
CoCl2 + Na2HPO4 = CoHPO4 + 2 NaCl
CH2Cl2 + Br = CH2Cl2Br =>
CH2Cl2 + Br = CH2Cl2Br
U3O8 = UO3 + UO2 =>
U3O8 = 2 UO3 + UO2
NaHCO3(s) + CaCl2(s) = CaCO3(s) + NaCl(aq) + HCl(aq) =>
NaHCO3(s) + CaCl2(s) = CaCO3(s) + NaCl(aq) + HCl(aq)
P + Ce2 = PCe5 =>
2 P + 5 Ce2 = 2 PCe5
FeSO4 + HBrO + HCl = Fe2(SO4)3 + FeCl3 + HBr + H2O =>
6 FeSO4 + 3 HBrO + 6 HCl = 2 Fe2(SO4)3 + 2 FeCl3 + 3 HBr + 3 H2O
PbCO3 + H2CO3 = Pb(HCO3)2 =>
PbCO3 + H2CO3 = Pb(HCO3)2
Al2C3 + H2O = Al(OH)3 + C2H4 =>
2 Al2C3 + 12 H2O = 4 Al(OH)3 + 3 C2H4
N2O5 + NaOH = NaNO3 + H2O =>
N2O5 + 2 NaOH = 2 NaNO3 + H2O
FeSO4 + HBrO + HCl = FeCl3 + FeBr3 + Fe2(SO4)3 + H2O =>
6 FeSO4 + 3 HBrO + 3 HCl = FeCl3 + FeBr3 + 2 Fe2(SO4)3 + 3 H2O
Cu2(Fe(CN)6) + NaOH = Na4(Fe(CN)6) + Cu(OH)2 =>
Cu2(Fe(CN)6) + 4 NaOH = Na4(Fe(CN)6) + 2 Cu(OH)2
KOH + BeSO4 = K2SO4 + Be(OH)2 =>
2 KOH + BeSO4 = K2SO4 + Be(OH)2
FeSO4 + HBrO + HCl = FeCl3 + FeBr3 + Fe2(SO4)3 + H2O =>
6 FeSO4 + 3 HBrO + 3 HCl = FeCl3 + FeBr3 + 2 Fe2(SO4)3 + 3 H2O
FeCl3 + KNO2 = Fe(NO2)3 + KCl =>
FeCl3 + 3 KNO2 = Fe(NO2)3 + 3 KCl
CoCl2 + Na2HPO4 = Co3(PO4)2 + NaH2PO4 + NaCl =>
3 CoCl2 + 4 Na2HPO4 = Co3(PO4)2 + 2 NaH2PO4 + 6 NaCl
FeO + N2O3 = Fe(NO2)2 =>
FeO + N2O3 = Fe(NO2)2
Ba(NO3)2 + Na2(CrO4) = BaCrO4 + Na(NO3) =>
Ba(NO3)2 + Na2(CrO4) = BaCrO4 + 2 Na(NO3)
FeSO4 + HBrO + HCl = FeCl3 + H2SO4 + HBr + H2O =>
2 FeSO4 + HBrO + 6 HCl = 2 FeCl3 + 2 H2SO4 + HBr + H2O
NaNO2H2O2 = NaNO3H2O =>
NaNO2H2O2 = NaNO3H2O
KHP(aq) + NaOH(aq) = H2O + NaKP =>
KHP(aq) + NaOH(aq) = H2O + NaKP
KHCO3 + HClO4 = KClO4 + H2CO3 =>
KHCO3 + HClO4 = KClO4 + H2CO3
HF + CuO = CuF2 + H2O =>
2 HF + CuO = CuF2 + H2O
FeSO4 + HBrO + HCl = Fe2(SO4)3 + FeCl3 + HBr + H2O =>
6 FeSO4 + 3 HBrO + 6 HCl = 2 Fe2(SO4)3 + 2 FeCl3 + 3 HBr + 3 H2O
C2H2 + KMnO4 + KOH = K2C2O4 + K2MnO4 + H2O =>
C2H2 + 8 KMnO4 + 10 KOH = K2C2O4 + 8 K2MnO4 + 6 H2O
Ba(NO3)2 + Na2(CrO4) = Ba(CrO4) + Na(NO3) =>
Ba(NO3)2 + Na2(CrO4) = Ba(CrO4) + 2 Na(NO3)
Br{-} + Cr2O7{2-} + H{+} = Br2 + Cr{3+} + H2O(milieuacide) =>
6 Br{-} + Cr2O7{2-} + 14 H{+} = 3 Br2 + 2 Cr{3+} + 7 H2O(milieuacide)
CH3Cl + CuO + O2 = CuCl + CO2 + H2O =>
4 CH3Cl + 4 CuO + 5 O2 = 4 CuCl + 4 CO2 + 6 H2O
Ni(NO3)2(aq) + Na2CO3(aq) = NiCO3(aq) + NaNO3(aq) =>
Ni(NO3)2(aq) + Na2CO3(aq) = NiCO3(aq) + 2 NaNO3(aq)
NiCl2 + Na2HPO4 = Ni3(PO4)2 + NaCl + HCl =>
3 NiCl2 + 2 Na2HPO4 = Ni3(PO4)2 + 4 NaCl + 2 HCl
NH4NO3 = N2 + O2 + H2O =>
2 NH4NO3 = 2 N2 + O2 + 4 H2O
G = G2 =>
2 G = G2
KHP(aq) + NaOH(aq) = H2O(aq) + NaKP(aq) =>
KHP(aq) + NaOH(aq) = H2O(aq) + NaKP(aq)
TiCl4 + HOH = TiO2 + HCl =>
TiCl4 + 2 HOH = TiO2 + 4 HCl
FeSO4 + HBrO + HCl = FeCl3 + H2SO4 + HBr + H2O =>
2 FeSO4 + HBrO + 6 HCl = 2 FeCl3 + 2 H2SO4 + HBr + H2O
CH3CH2COONa + O2 = CO2 + H2O + Na =>
4 CH3CH2COONa + 13 O2 = 12 CO2 + 10 H2O + 4 Na
Balance the equation of any chemical reaction
| Equations balanced on the previous day |
Equations balanced on 11/15/24
Equations balanced on 12/15/23
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