| Equations balanced on the previous day |
[Cu(NH3)4]SO4*H2O + BaCl2 = Cu(Cl)2 + BaSO4 + 4 NH3 + H2O
ZnCO3 + CH3COOH = CH3COOZn + CO2 + H2O =>
8 ZnCO3 + 9 CH3COOH = 8 CH3COOZn + 10 CO2 + 6 H2O
(NH4)2MoO4 + SnCl2 + HCl = MoCl3 + SnCl4 + NH4Cl + H2O =>
2(NH4)2MoO4 + 3 SnCl2 + 16 HCl = 2 MoCl3 + 3 SnCl4 + 4 NH4Cl + 8 H2O
C2H5 + Cl2 = C + HCl =>
2 C2H5 + 5 Cl2 = 4 C + 10 HCl
(NH4)2MoO4 + HCl + SnCl2 = Mo5O14 + SnCl4 + NH4Cl + H2O =>
5(NH4)2MoO4 + 12 HCl + SnCl2 = Mo5O14 + SnCl4 + 10 NH4Cl + 6 H2O
NaI + PbSO4 = PbI2 + Na2SO4 =>
2 NaI + PbSO4 = PbI2 + Na2SO4
BaSO4 + HCl = BaCl2 + H2O + SO3 =>
BaSO4 + 2 HCl = BaCl2 + H2O + SO3
KBr + H2SO4 + KMnO4 = MnSO4 + Br2 + K2SO4 + H2O =>
10 KBr + 8 H2SO4 + 2 KMnO4 = 2 MnSO4 + 5 Br2 + 6 K2SO4 + 8 H2O
(NH4)2MoO4 + HCl + SnCl2 = Mo4O10(OH)2 + SnCl4 + NH4Cl + H2O =>
4(NH4)2MoO4 + 10 HCl + SnCl2 = Mo4O10(OH)2 + SnCl4 + 8 NH4Cl + 4 H2O
HClNaOH = NaClH2O =>
HClNaOH = NaClH2O
Ba(NO3)2 + Fe2(SO4)3 = BaSO4 + Fe(NO3)3 =>
3 Ba(NO3)2 + Fe2(SO4)3 = 3 BaSO4 + 2 Fe(NO3)3
Na2(CO3) + HNO3 = Na(NO3) + CO2 + H2O =>
Na2(CO3) + 2 HNO3 = 2 Na(NO3) + CO2 + H2O
Na2B4O7*10H2O = NaB(OH)4 + B(OH)3 + H2O =>
Na2B4O7*10H2O = 2 NaB(OH)4 + 2 B(OH)3 + 3 H2O
Na2B4O7*10H2O = H3BO3 + NaOH + H2O =>
Na2B4O7*10H2O = 4 H3BO3 + 2 NaOH + 3 H2O
BrO3 + KI = BrI + KO3 =>
BrO3 + KI = BrI + KO3
CrBr2 + KOH = Cr(OH)2 + KBr =>
CrBr2 + 2 KOH = Cr(OH)2 + 2 KBr
Al2O3*2H2O + H2SO4 = Al2(SO4)3 + H2O =>
Al2O3*2H2O + 3 H2SO4 = Al2(SO4)3 + 5 H2O
NH2O = NH4NO2 =>
2 NH2O = NH4NO2
Cu{2+} + H2O + H2 = Cu + H3O{+} =>
Cu{2+} + 2 H2O + H2 = Cu + 2 H3O{+}
Fe2(CO3)3 + Ba(NO3)2 = Fe(NO3)3 + BaCO3 =>
Fe2(CO3)3 + 3 Ba(NO3)2 = 2 Fe(NO3)3 + 3 BaCO3
Na2S2O3 + BaCl2 = BaS2O3 + NaCl =>
Na2S2O3 + BaCl2 = BaS2O3 + 2 NaCl
MnO2 + Sn(OH)4 = MnOH + Sn(O2)4 =>
4 MnO2 + Sn(OH)4 = 4 MnOH + Sn(O2)4
Na2B4O7*10H2O = H3BO3 + NaBO2 + H2O =>
Na2B4O7*10H2O = 2 H3BO3 + 2 NaBO2 + 7 H2O
Al + Fe2O6 = Fe + AlO =>
6 Al + Fe2O6 = 2 Fe + 6 AlO
Na3PO4 + CaCO3 = Ca3(PO4)2 + Na2CO3 =>
2 Na3PO4 + 3 CaCO3 = Ca3(PO4)2 + 3 Na2CO3
CO2 + H2O + NH3 = H2NCH2COOH + O2 =>
4 CO2 + 2 H2O + 2 NH3 = 2 H2NCH2COOH + 3 O2
Fe2 + Co3 = Fe3Co4 =>
9 Fe2 + 8 Co3 = 6 Fe3Co4
Cu2SO4 + KNO3 = K2SO4 + CuNO3 =>
Cu2SO4 + 2 KNO3 = K2SO4 + 2 CuNO3
CH3CH2CH2CH2OH + HCl + ZnCl2 = CH3CH2CH2CH2CH2ClCl2 + Zn + H2O =>
5 CH3CH2CH2CH2OH + 4 HCl + 4 ZnCl2 = 4 CH3CH2CH2CH2CH2ClCl2 + 4 Zn + 5 H2O
CH3COOH + Cu = Cu(CH3COOH) =>
CH3COOH + Cu = Cu(CH3COOH)
AgNO3 + CrO4 = AgO4 + CrNO3 =>
AgNO3 + CrO4 = AgO4 + CrNO3
HCl + NaO2H = NaClO + H2O =>
HCl + NaO2H = NaClO + H2O
NO2 + KClO3 + KOH = KCl + H2O + KNO3 =>
6 NO2 + KClO3 + 6 KOH = KCl + 3 H2O + 6 KNO3
Na4[Fe(Cn)6] + Fe3 = Fe4[Fe(Cn)6]3 + Na =>
9 Na4[Fe(Cn)6] + 4 Fe3 = 3 Fe4[Fe(Cn)6]3 + 36 Na
Na2B4O7*10H2O = Na2O + B2O3 + H2O =>
Na2B4O7*10H2O = Na2O + 2 B2O3 + 10 H2O
KPr + AuN = KPrAuN =>
KPr + AuN = KPrAuN
HBrO4 + Al(OH)3 = Al(BrO4)3 + H2O =>
3 HBrO4 + Al(OH)3 = Al(BrO4)3 + 3 H2O
P + NaOH = Na3PO3 + PH3 =>
2 P + 3 NaOH = Na3PO3 + PH3
CaCl3 + HCl = CaCl + HCl3 =>
CaCl3 + HCl = CaCl + HCl3
(C8H18O2) + O2 = CO2 + H2O =>
2(C8H18O2) + 23 O2 = 16 CO2 + 18 H2O
Na2B4O7*10H2O = Na + B4O7 + H2O =>
Na2B4O7*10H2O = 2 Na + B4O7 + 10 H2O
K + CuCl = KCl + Cu =>
K + CuCl = KCl + Cu
SrHPO4 + CH3COOH = Sr(CH3COO)2 + H3PO4 =>
SrHPO4 + 2 CH3COOH = Sr(CH3COO)2 + H3PO4
CH4N2O + HNO3 = CH5N3O4 =>
CH4N2O + HNO3 = CH5N3O4
Zn + HCl = ZnCl2 + H2 = =>
Zn + 2 HCl = ZnCl2 + H2
Ag2CO3 + H2SO4 = Ag2SO4 + H2CO3 =>
Ag2CO3 + H2SO4 = Ag2SO4 + H2CO3
SnCl2 + K2Cr2O7 + H2SO4 = Sn(SO4)2 + SnCl4 + Cr2(SO4) + K2SO4 + H2O =>
10 SnCl2 + 2 K2Cr2O7 + 14 H2SO4 = 5 Sn(SO4)2 + 5 SnCl4 + 2 Cr2(SO4) + 2 K2SO4 + 14 H2O
NH3 + O2 = N2 + H2O =>
4 NH3 + 3 O2 = 2 N2 + 6 H2O
Pt + F2 = Pt4F4 =>
4 Pt + 2 F2 = Pt4F4
K2(Cr2O7) + H2SO4 = K2SO4 + Cr2(SO4)3 + O + H2O =>
K2(Cr2O7) + 4 H2SO4 = K2SO4 + Cr2(SO4)3 + 3 O + 4 H2O
Balance the equation of any chemical reaction
| Equations balanced on the previous day |
Equations balanced on 11/13/24
Equations balanced on 12/13/23
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