Equations balanced on the previous day |
FeCl2 + 6 HNO3 = Cl2 + Fe(NO3)3 + 3 H2O + 3 NO2
Cu + PbS = CuS + Pb =>
Cu + PbS = CuS + Pb
Fe2SO4*7H2O = H2O + Fe2SO4 =>
Fe2SO4*7H2O = 7 H2O + Fe2SO4
Sr(OH)2 + NaH2PO4 = SrHPO4 + NaOH + H2O =>
Sr(OH)2 + NaH2PO4 = SrHPO4 + NaOH + H2O
H2SO4 + Zn = H2 + ZnSO4 =>
H2SO4 + Zn = H2 + ZnSO4
Pb(NO3)2 + HOH = Pb(OH)2 + (HNO3) =>
Pb(NO3)2 + 2 HOH = Pb(OH)2 + 2(HNO3)
C2H6 + NaOH = C2H5OH + Na + H2O =>
C2H6 + 2 NaOH = C2H5OH + 2 Na + H2O
Al2O3 + NaOH = Al(OH)3 + Na2O =>
Al2O3 + 6 NaOH = 2 Al(OH)3 + 3 Na2O
FeCl2 + H2SO4 = Fe2(SO4)3 + HCl + SO2 + H2O =>
2 FeCl2 + 4 H2SO4 = Fe2(SO4)3 + 4 HCl + SO2 + 2 H2O
C6H10(g) + O2(g) = CO2(g) + H2O(l) =>
2 C6H10(g) + 17 O2(g) = 12 CO2(g) + 10 H2O(l)
C6H12O6 + O2 = CO2 + H2O =>
C6H12O6 + 6 O2 = 6 CO2 + 6 H2O
FeAsS + NO3{-} + H{+} = Fe{3+} + AsO4{3-} + SO4{2-} + NO + H2O =>
3 FeAsS + 14 NO3{-} + 8 H{+} = 3 Fe{3+} + 3 AsO4{3-} + 3 SO4{2-} + 14 NO + 4 H2O
Cl2 + KI = I2 + KCl =>
Cl2 + 2 KI = I2 + 2 KCl
KMnO4 + H2O2 = KOH + MnO2 + O2 =>
2 KMnO4 + H2O2 = 2 KOH + 2 MnO2 + 2 O2
Sr(OH)2 + NaHSO3 = NaOH + H2SO4 + Sr =>
Sr(OH)2 + NaHSO3 = NaOH + H2SO4 + Sr
Ba(CH3COO)2 + Na2SO3 = BaSO3 + NaCH3COO =>
Ba(CH3COO)2 + Na2SO3 = BaSO3 + 2 NaCH3COO
[Zn(H2O)6]{2+} + NH4OH = [Zn(NH3)6]{2+} + H2O =>
[Zn(H2O)6]{2+} + 6 NH4OH = [Zn(NH3)6]{2+} + 12 H2O
FeS + O2 = SO2Fe =>
FeS + O2 = SO2Fe
Ba(OH)2 + Cl2 = BaCl2 + Ba(ClO)2 + H2O =>
2 Ba(OH)2 + 2 Cl2 = BaCl2 + Ba(ClO)2 + 2 H2O
Cd(OH)2 + HCl = CdOHCl + H2O =>
Cd(OH)2 + HCl = CdOHCl + H2O
HCl + H2PO4 = H3PO4 + Cl =>
HCl + H2PO4 = H3PO4 + Cl
(NH4)2SO3 + Ni(NO3)2 = Ni2(SO3)2 + NH4NO3 =>
2(NH4)2SO3 + 2 Ni(NO3)2 = Ni2(SO3)2 + 4 NH4NO3
Cu2(OH)2SO4 + NH4OH = [Cu(NH3)4](OH)2 + (NH4)2SO4 + H2O =>
Cu2(OH)2SO4 + 10 NH4OH = 2[Cu(NH3)4](OH)2 + (NH4)2SO4 + 8 H2O
KMnO4 + Na2SO3 = MnO2 + NaO + KSO3 =>
KMnO4 + Na2SO3 = MnO2 + 2 NaO + KSO3
CaO + NO = CaNO2 =>
CaO + NO = CaNO2
PH3 + KMnO4 + H2SO4 = K2SO4 + MnSO4 + H3PO4 + H2O =>
5 PH3 + 8 KMnO4 + 12 H2SO4 = 4 K2SO4 + 8 MnSO4 + 5 H3PO4 + 12 H2O
U(SO4)2 + O2 + H2O = UO2SO4 + H2SO4 =>
2 U(SO4)2 + O2 + 2 H2O = 2 UO2SO4 + 2 H2SO4
H2SO4 + Na2C2O4 = H2C2O4 + Na2SO4 =>
H2SO4 + Na2C2O4 = H2C2O4 + Na2SO4
Cr23C6 + O2 = Cr2O3 + C =>
4 Cr23C6 + 69 O2 = 46 Cr2O3 + 24 C
NaHSO3 + Cl2 + NaOH = Na2SO4 + NaCl + H2O =>
NaHSO3 + Cl2 + 3 NaOH = Na2SO4 + 2 NaCl + 2 H2O
BaCl2 + H2SO4 = BaSO4 + HCl =>
BaCl2 + H2SO4 = BaSO4 + 2 HCl
Fe + H2C2O4 + H2O = FeC2O4H2O + H =>
Fe + H2C2O4 + H2O = FeC2O4H2O + 2 H
MgCO3 + HCl = MgCl2 + H2O + (CO2)2 =>
2 MgCO3 + 4 HCl = 2 MgCl2 + 2 H2O + (CO2)2
CuI2 + Cl2 = CuCl2 + I2 =>
CuI2 + Cl2 = CuCl2 + I2
NaNO2 + Na2S2O5 + CH3COOH = Na{+} + HON(SO3)2{2-} + CH3COONa =>
NaNO2 + Na2S2O5 + CH3COOH = 2 Na{+} + HON(SO3)2{2-} + CH3COONa
Na2CO3 = Na2O + CO2 =>
Na2CO3 = Na2O + CO2
Zn + CuO4S = ZnSO4 + Cu =>
Zn + CuO4S = ZnSO4 + Cu
Cu(NO3)2(aq) + Na2CO3(s) + H2O(l) = CuCO3*Cu(OH)2(s) + NaNO3(aq) + CO2(g) =>
2 Cu(NO3)2(aq) + 2 Na2CO3(s) + H2O(l) = CuCO3*Cu(OH)2(s) + 4 NaNO3(aq) + CO2(g)
MnO4{-} + HSO3{-} + OH{-} = MnO2 + SO4{2-} + H2O =>
2 MnO4{-} + 3 HSO3{-} + OH{-} = 2 MnO2 + 3 SO4{2-} + 2 H2O
(NH4)2CO3 + H2O = H2CO3 + NH4OH =>
(NH4)2CO3 + 2 H2O = H2CO3 + 2 NH4OH
NaJ + KMnO4 + H2SO4 = J2 + K2SO4 + MnSO4 + Na2SO4 + H2O =>
10 NaJ + 2 KMnO4 + 8 H2SO4 = 5 J2 + K2SO4 + 2 MnSO4 + 5 Na2SO4 + 8 H2O
(Zn(CH3COO)2)2H2O + NaOH = ZnO + NaCH3COO + H2O =>
(Zn(CH3COO)2)2H2O + 4 NaOH = 2 ZnO + 4 NaCH3COO + 3 H2O
SbPO4 + HNO3 = H3PO4 + Sb(NO3)3 =>
SbPO4 + 3 HNO3 = H3PO4 + Sb(NO3)3
ZnBr2 + Cl2 = ZnCl2 + Br2 =>
ZnBr2 + Cl2 = ZnCl2 + Br2
N2H6SO4 + KMnO4 + H2SO4 = K2SO4 + MnSO4 + N2 + H2O =>
5 N2H6SO4 + 4 KMnO4 + H2SO4 = 2 K2SO4 + 4 MnSO4 + 5 N2 + 16 H2O
KJ + H2SO4 = K2SO4 + HJ =>
2 KJ + H2SO4 = K2SO4 + 2 HJ
ZnO + BaSO4 = BaZnO2 + SO3 =>
ZnO + BaSO4 = BaZnO2 + SO3
Zn + HCl = ZnCl2 + H2 = =>
Zn + 2 HCl = ZnCl2 + H2
ClCH2COOH + NaHCO3 = ClCH2COONa + H2O + CO2 =>
ClCH2COOH + NaHCO3 = ClCH2COONa + H2O + CO2
K2CrO4 + H3PO4 = K2Cr2O7 + K3PO4 + H2O =>
6 K2CrO4 + 2 H3PO4 = 3 K2Cr2O7 + 2 K3PO4 + 3 H2O
Balance the equation of any chemical reaction
Equations balanced on the previous day |
Equations balanced on 10/29/24
Equations balanced on 11/28/23
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