Equations balanced on the previous day |
Co(OH)2 + 2 H = Co + 2 H2O
CoCl2*6H2O + NH4Cl + NH3 + H2O2 = [Co(NH3)5]Cl3 + H2O =>
2 CoCl2*6H2O + 2 NH4Cl + 8 NH3 + H2O2 = 2[Co(NH3)5]Cl3 + 14 H2O
KMnO4 + Mn(CH3COO)2 = MnO2 + KOH + COH =>
2 KMnO4 + Mn(CH3COO)2 = 3 MnO2 + 2 KOH + 4 COH
Mn(NO3)2(aq) + Na3PO4(aq) = Mn(PO4)2 + Na3(NO3) =>
Mn(NO3)2(aq) + 2 Na3PO4(aq) = Mn(PO4)2 + 2 Na3(NO3)
Fe + HCl + H2O = Cl2Fe*4H2O + H2 =>
Fe + 2 HCl + 4 H2O = Cl2Fe*4H2O + H2
HCl + NaF = NaCl + HF =>
HCl + NaF = NaCl + HF
PbBr2 + Al2O3 = PbO + AlBr3 =>
3 PbBr2 + Al2O3 = 3 PbO + 2 AlBr3
(NH4)(NO3) + NaOH = Na(NO3) + NH3 + H2O =>
(NH4)(NO3) + NaOH = Na(NO3) + NH3 + H2O
TiOSO4 + H2O + NaOH = Ti(OH)4 + Na2SO4 =>
TiOSO4 + H2O + 2 NaOH = Ti(OH)4 + Na2SO4
YBa2Cu3O7 + HCl = CuCl + H2O + YCl3 + BaCl2 + Cl2 =>
YBa2Cu3O7 + 14 HCl = 3 CuCl + 7 H2O + YCl3 + 2 BaCl2 + 2 Cl2
PbS + HCl + HNO3 = H2[PbCl4] + H2SO4 + NO + H2O =>
3 PbS + 12 HCl + 8 HNO3 = 3 H2[PbCl4] + 3 H2SO4 + 8 NO + 4 H2O
H2SO4 + BaI2 = H2S + BaSO4 + I2 + H2O =>
5 H2SO4 + 4 BaI2 = H2S + 4 BaSO4 + 4 I2 + 4 H2O
ZnSO4(aq) + NaOH(aq) = Zn(OH)2(aq) + Na2SO4(aq) =>
ZnSO4(aq) + 2 NaOH(aq) = Zn(OH)2(aq) + Na2SO4(aq)
C6H12O6 = C905 + H345 + O342 =>
754317.5C6H12O6 = 5001 C905 + 26237.130434783H345 + 13233.640350877O342
Al2O3 + H2O + NaOH = NaAl(OH)4 =>
Al2O3 + 3 H2O + 2 NaOH = 2 NaAl(OH)4
H2SO4 + Mg = MgSO4 + SO2 + H2O =>
2 H2SO4 + Mg = MgSO4 + SO2 + 2 H2O
CuF2 + Li = CuLi + F =>
CuF2 + Li = CuLi + 2 F
K + CH3OH = CH3OK + H2 =>
2 K + 2 CH3OH = 2 CH3OK + H2
NiSO4 + NH4OH = Ni(OH)2 + (NH4)2SO4 =>
NiSO4 + 2 NH4OH = Ni(OH)2 + (NH4)2SO4
BaCl + FeSO = BaSO + FeCl =>
BaCl + FeSO = BaSO + FeCl
K2SO3 + HOH = KOH + H2SO3 =>
K2SO3 + 2 HOH = 2 KOH + H2SO3
AlI3 + Zn(C2H3O2)2 = Al(C2H3O2)3 + ZnI2 =>
2 AlI3 + 3 Zn(C2H3O2)2 = 2 Al(C2H3O2)3 + 3 ZnI2
(NH4)2S + HCl = (NH4)Cl + H2S =>
(NH4)2S + 2 HCl = 2(NH4)Cl + H2S
FeCl3 + NaOH = (Fe(OH)3) + (NaCl) =>
FeCl3 + 3 NaOH = (Fe(OH)3) + 3(NaCl)
CoCl2*6H2O + H2O2 + HCl + C2H8N2 = Co(C2H8N2)3Cl3 + H2O =>
2 CoCl2*6H2O + H2O2 + 2 HCl + 6 C2H8N2 = 2 Co(C2H8N2)3Cl3 + 14 H2O
HNO3 + H2S = NO + S + H2O =>
2 HNO3 + 3 H2S = 2 NO + 3 S + 4 H2O
NiCl2(aq) + Pb(NO3)2(aq) = Ni(NO3)2(aq) + PbCl2(aq) =>
NiCl2(aq) + Pb(NO3)2(aq) = Ni(NO3)2(aq) + PbCl2(aq)
Fe + NaCl = Na + FeCl2 =>
Fe + 2 NaCl = 2 Na + FeCl2
MgCl2 + NaOH = Mg(OH)2 + NaCl =>
MgCl2 + 2 NaOH = Mg(OH)2 + 2 NaCl
As2S3 + HNO3 + H2O = H2SO4 + H3AsO4 + NO =>
3 As2S3 + 28 HNO3 + 4 H2O = 9 H2SO4 + 6 H3AsO4 + 28 NO
CaS + C2H4O2 = CaC2H4O2 + S =>
CaS + C2H4O2 = CaC2H4O2 + S
Sn(s) + HNO3(aq) = SnNO3(s) + H2(g) =>
2 Sn(s) + 2 HNO3(aq) = 2 SnNO3(s) + H2(g)
Al2(SO4)3 + K3PO4 = Al2PO4 + K3(SO4)3 =>
Al2(SO4)3 + K3PO4 = Al2PO4 + K3(SO4)3
C17H19NO3 + (CH3CO)2O = C21H23NO5 + CH3COOH =>
C17H19NO3 + 2(CH3CO)2O = C21H23NO5 + 2 CH3COOH
C2H5OH + H2O2 = C7H6O3 + H2O =>
7 C2H5OH + 14 H2O2 = 2 C7H6O3 + 29 H2O
Pb(NO3)2(aq) + NACl(aq) = PbCl2(aq) + NANO3(aq) =>
Pb(NO3)2(aq) + 2 NACl(aq) = PbCl2(aq) + 2 NANO3(aq)
C6H12(l) + O(g) = CO2(g) + H2O(l) =>
C6H12(l) + 18 O(g) = 6 CO2(g) + 6 H2O(l)
Bi2(SO4)3 + H2O = Bi + O2 + H2SO4 =>
2 Bi2(SO4)3 + 6 H2O = 4 Bi + 3 O2 + 6 H2SO4
PH3 + O2 = P2O5 + H2O =>
2 PH3 + 4 O2 = P2O5 + 3 H2O
H2SO4 + AgNO3 = Ag2SO4 + HNO3 =>
H2SO4 + 2 AgNO3 = Ag2SO4 + 2 HNO3
H2(g) + P4(s) + O2(g) = H3PO4(l) =>
6 H2(g) + P4(s) + 8 O2(g) = 4 H3PO4(l)
H3CNH2 + HCl = H3CNH3 + Cl =>
H3CNH2 + HCl = H3CNH3 + Cl
HCl + NaOH = NaCl + H2O =>
HCl + NaOH = NaCl + H2O
H2(CO3) + Fe2(C2O4)3 = H2(C2O4)3 + Fe2(CO3) =>
H2(CO3) + Fe2(C2O4)3 = H2(C2O4)3 + Fe2(CO3)
KCrO4 + Pb(NO3)2 = KNO3 + Pb(CrO4)2 =>
2 KCrO4 + Pb(NO3)2 = 2 KNO3 + Pb(CrO4)2
NaNO3 + Ba3(PO4)2 = Na3PO4 + Ba(NO3)2 =>
6 NaNO3 + Ba3(PO4)2 = 2 Na3PO4 + 3 Ba(NO3)2
Ag{+} + Pb{2+} + OH{-} = Ag + PbO2 + H2O =>
2 Ag{+} + Pb{2+} + 4 OH{-} = 2 Ag + PbO2 + 2 H2O
FeCl2 + NH4SCN = [FeSCN]Cl + NH4Cl =>
FeCl2 + NH4SCN = [FeSCN]Cl + NH4Cl
I2O5(s) + CO(g) = CO2(g) + I2(g) =>
I2O5(s) + 5 CO(g) = 5 CO2(g) + I2(g)
BeH2 + NaH2 = NaBeH4 =>
BeH2 + NaH2 = NaBeH4
Balance the equation of any chemical reaction
Equations balanced on the previous day |
Equations balanced on 10/15/24
Equations balanced on 11/14/23
Please let us know how we can improve this web app.