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Chemical Equations Balanced on 08/03/24

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Balance the equation of any chemical reaction
Na2S + HClO = NaClO + H2S =>
Na2S + 2 HClO = 2 NaClO + H2S

Al + CuSO4 = Al3(SO4) + Cu =>
3 Al + CuSO4 = Al3(SO4) + Cu

K2CO3 + H2SO4 = K2SO4 + H2CO3 =>
K2CO3 + H2SO4 = K2SO4 + H2CO3

C2H2 + KMnO4 = C2K2O4 + MnO2 + KOH + H2O =>
3 C2H2 + 8 KMnO4 = 3 C2K2O4 + 8 MnO2 + 2 KOH + 2 H2O

[Co(NH3)6]Cl2 + O2 + NH4Cl = NH3 + H2O + [Co(NH3)6]Cl3 =>
4[Co(NH3)6]Cl2 + O2 + 4 NH4Cl = 4 NH3 + 2 H2O + 4[Co(NH3)6]Cl3

C5H9O2 + O2 = CO2 + H2O =>
4 C5H9O2 + 25 O2 = 20 CO2 + 18 H2O

CO3(NH4)2 + Sr(OH)2 = SrCO3 + NH4OH =>
CO3(NH4)2 + Sr(OH)2 = SrCO3 + 2 NH4OH

KOH + Na2Cr2O7 + HCl = NaCl + H2O + K2Cr2O7 =>
2 KOH + Na2Cr2O7 + 2 HCl = 2 NaCl + 2 H2O + K2Cr2O7

NH3 + O2 = NO + H2O =>
4 NH3 + 5 O2 = 4 NO + 6 H2O

Cr(OH)3 + KClO3 + KOH = K2CrO4 + Cl + H2O =>
5 Cr(OH)3 + 3 KClO3 + 7 KOH = 5 K2CrO4 + 3 Cl + 11 H2O

C2H2 = C6H6 =>
3 C2H2 = C6H6

NH3 + O2 = NO + H2O =>
4 NH3 + 5 O2 = 4 NO + 6 H2O

C9H8O4 + NaHCO3 = C9H7NaO4 + CO2 + H2O =>
C9H8O4 + NaHCO3 = C9H7NaO4 + CO2 + H2O

HNO2 + LiOH = LiNO2 + HOH =>
HNO2 + LiOH = LiNO2 + HOH

CH2O + Cu(OH)2 + NaOH = HCOONa + Cu + H2O =>
CH2O + Cu(OH)2 + NaOH = HCOONa + Cu + 2 H2O

CH3CCH3CH3OH + HCl = CH3CCH3CH3Cl + H2O =>
CH3CCH3CH3OH + HCl = CH3CCH3CH3Cl + H2O

CsOH + HCI = CsCI + H2O =>
CsOH + HCI = CsCI + H2O

Ca(NO3)2 + NaI = CaI2 + NaNO3 =>
Ca(NO3)2 + 2 NaI = CaI2 + 2 NaNO3

Ba(NO3)2 + CuSO4 = Ba(NO3)2CuSO4 =>
Ba(NO3)2 + CuSO4 = Ba(NO3)2CuSO4

FeSO4*7H2O + KMnO4 + H2SO4 = Fe2(SO4)3 + H2O + K2SO4 + MnSO4 =>
10 FeSO4*7H2O + 2 KMnO4 + 8 H2SO4 = 5 Fe2(SO4)3 + 78 H2O + K2SO4 + 2 MnSO4

C2H3Br + KOH = C2H4 + KBr + O2 =>
2 C2H3Br + 2 KOH = 2 C2H4 + 2 KBr + O2

Er2S3 + Er2O3 + Ta2O5 = Er3TaO4S3 =>
2 Er2S3 + Er2O3 + Ta2O5 = 2 Er3TaO4S3

KHCO3 + BaCl2 = KCl + Ba(HCO3)2 =>
2 KHCO3 + BaCl2 = 2 KCl + Ba(HCO3)2

CrCl3 + H2O = [Cr(H2O)6]Cl3 =>
CrCl3 + 6 H2O = [Cr(H2O)6]Cl3

Mn(NO3)2(aq) + K2CrO4(aq) = MnCrO4 + KNO3 =>
Mn(NO3)2(aq) + K2CrO4(aq) = MnCrO4 + 2 KNO3

Zn(OH)2 + K4[Fe(CN)6] = Zn3K2[Fe(CN)6]2 + KOH =>
3 Zn(OH)2 + 2 K4[Fe(CN)6] = Zn3K2[Fe(CN)6]2 + 6 KOH

NaBH4(s) + H2SO4(aq) = B2H6(g) + H2(g) + Na2SO4(aq) =>
2 NaBH4(s) + H2SO4(aq) = B2H6(g) + 2 H2(g) + Na2SO4(aq)

C2H4 + F2 = C2H4F2 =>
C2H4 + F2 = C2H4F2

AgCl + NH4Cl = [Ag(NH3)2]Cl + HCl =>
AgCl + 2 NH4Cl = [Ag(NH3)2]Cl + 2 HCl

K2(SO4) + SrCl2 = KCl + Sr(SO4) =>
K2(SO4) + SrCl2 = 2 KCl + Sr(SO4)

[Co(NH3)6]Cl2 + O2 + NH4Cl = NH3 + H2O + [Co(NH3)6]Cl3 =>
4[Co(NH3)6]Cl2 + O2 + 4 NH4Cl = 4 NH3 + 2 H2O + 4[Co(NH3)6]Cl3

NaI + Fe(NO3)4 = NaNO3 + FeI4 =>
4 NaI + Fe(NO3)4 = 4 NaNO3 + FeI4

Ag2SO4 + NaCl = Na2SO4 + AgCl =>
Ag2SO4 + 2 NaCl = Na2SO4 + 2 AgCl

HCl + CuS = CuCl2 + H2S =>
2 HCl + CuS = CuCl2 + H2S

C2H4 + KMnO4 + H2SO4 = H2C2O4 + K2SO4 + MnSO4 + H2O =>
C2H4 + 2 KMnO4 + 3 H2SO4 = H2C2O4 + K2SO4 + 2 MnSO4 + 4 H2O

K2O + N2 = K + KNO3 =>
6 K2O + N2 = 10 K + 2 KNO3

PN + K2Cr2O7 + H2SO4 = H3PO4 + K2SO4 + Cr2(SO4)3 + NO + H2O =>
6 PN + 7 K2Cr2O7 + 28 H2SO4 = 6 H3PO4 + 7 K2SO4 + 7 Cr2(SO4)3 + 6 NO + 19 H2O

C2H4O2 + H2 = C4H8O2 + H2O =>
2 C2H4O2 + 2 H2 = C4H8O2 + 2 H2O

(NH4)2Cr2O7 + KOH = K2Cr2O7 + NH3 + H2O =>
(NH4)2Cr2O7 + 2 KOH = K2Cr2O7 + 2 NH3 + 2 H2O

N2O + SO2 = N2S + O2 =>
2 N2O + 2 SO2 = 2 N2S + 3 O2

MnO2 + NaBiO3 + H2SO4 = HMnO4 + Bi2(SO4)3 + Na2SO4 + H2O =>
4 MnO2 + 6 NaBiO3 + 12 H2SO4 = 4 HMnO4 + 3 Bi2(SO4)3 + 3 Na2SO4 + 10 H2O

Ca + N2 = Ca3N2 =>
3 Ca + N2 = Ca3N2

MnO5 + HCl = MnCl2 + H2O + Cl2 =>
MnO5 + 10 HCl = MnCl2 + 5 H2O + 4 Cl2

C2H4O2 + H2O = CO2 + H2 =>
C2H4O2 + 2 H2O = 2 CO2 + 4 H2

Na2S2O3 + Br2 + NaOH = NaBr + Na2SO3 + H2O =>
Na2S2O3 + 2 Br2 + 6 NaOH = 4 NaBr + 2 Na2SO3 + 3 H2O

(a)Na2B4O7(s) + H2SO4(aq) + H2O(l) = H3BO3(s) + Na2SO4(aq) =>
(a)Na2B4O7(s) + H2SO4(aq) + 5 H2O(l) = 4 H3BO3(s) + Na2SO4(aq)

Cu(s) + Co2(s) = CuCo3 =>
2 Cu(s) + 3 Co2(s) = 2 CuCo3

Na2CO3 + HCl = NaCl + H2O + CO2 =>
Na2CO3 + 2 HCl = 2 NaCl + H2O + CO2

NH4Br + K2CO3 = KBr + (NH4)2CO3 =>
2 NH4Br + K2CO3 = 2 KBr + (NH4)2CO3

KCl + AgNO3 = AgCl + KNO3 =>
KCl + AgNO3 = AgCl + KNO3

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Balance the equation of any chemical reaction
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Equations balanced on 07/27/24
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Equations balanced on 08/03/23
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