Equations balanced on the previous day | Equations balanced on the next day |
HF + H2O = H3O + F
Cu + (HNO3)4 = Cu(NO3)2 + NO2 + H2O =>
Cu + (HNO3)4 = Cu(NO3)2 + 2 NO2 + 2 H2O
I2(s) + CI2(g) = ICI5(s) =>
2 I2(s) + CI2(g) = ICI5(s)
CH3CHO + Cr2O72{2-} + H{+} = CH3COOH + Cr3{+} + H2O =>
212 CH3CHO + 3 Cr2O72{2-} + 8 H{+} = 212 CH3COOH + 2 Cr3{+} + 4 H2O
Cu + FeS = CuS + Fe =>
Cu + FeS = CuS + Fe
Na2SO3 + KMnO4 + H2O = Na2SO4 + KOH + MnO2 =>
3 Na2SO3 + 2 KMnO4 + H2O = 3 Na2SO4 + 2 KOH + 2 MnO2
CaS + NaOH = Na2S + Ca(OH)2 =>
CaS + 2 NaOH = Na2S + Ca(OH)2
Na2SO4 + Pb(CH3CO2)2 = NaCH3CO2 + PbSO4 =>
Na2SO4 + Pb(CH3CO2)2 = 2 NaCH3CO2 + PbSO4
NaBF4 + NaN3 = BN + NaF + N2 =>
NaBF4 + 3 NaN3 = BN + 4 NaF + 4 N2
NaH2PO4HCl = H3PO4NaCl =>
NaH2PO4HCl = H3PO4NaCl
H2 + SO4 + Ca3(PO4)2 = CaSO4 + H3PO4 =>
3 H2 + 3 SO4 + Ca3(PO4)2 = 3 CaSO4 + 2 H3PO4
Mg + CO4 = MgO + C =>
4 Mg + CO4 = 4 MgO + C
H3PO2 + AgNO3 + H2O = H3PO4 + Ag + HNO3 =>
H3PO2 + 4 AgNO3 + 2 H2O = H3PO4 + 4 Ag + 4 HNO3
Na2CO3(s) + HCl(aq) = NaCl(s) + H2O(l) + CO2 =>
Na2CO3(s) + 2 HCl(aq) = 2 NaCl(s) + H2O(l) + CO2
Ni + AgCl = NiCl + Ag2 =>
2 Ni + 2 AgCl = 2 NiCl + Ag2
NaHSO3 + CuSO4 = H2SO3 + Na2SO4 + CuSO3 =>
2 NaHSO3 + CuSO4 = H2SO3 + Na2SO4 + CuSO3
Ag(s) + HNO3(aq) = AgNO3(aq) + H2O(l) + NO(g) =>
3 Ag(s) + 4 HNO3(aq) = 3 AgNO3(aq) + 2 H2O(l) + NO(g)
Ba(OH)2 + Mg(HCO3)2 = BaCO3 + Mg(OH)2 + H2O =>
2 Ba(OH)2 + Mg(HCO3)2 = 2 BaCO3 + Mg(OH)2 + 2 H2O
MgCl2(aq) + H2SO4(aq) = MgSO4 + HCl(aq) =>
MgCl2(aq) + H2SO4(aq) = MgSO4 + 2 HCl(aq)
HCl + Mg0 = MgCl2 + H2 =>
2 HCl + Mg0 = MgCl2 + H2
(CaO)3(Al2O3) + CaO(Al2O3)6 = (CaO)(Al2O3) =>
5(CaO)3(Al2O3) + 2 CaO(Al2O3)6 = 17(CaO)(Al2O3)
NaHSO4 + Al2O3 = Na2SO4 + Al2(SO4)3 + H2O =>
6 NaHSO4 + Al2O3 = 3 Na2SO4 + Al2(SO4)3 + 3 H2O
Cr + H2O + H2SO4 = [Cr(H2O)6]2(SO4)3 + H2 =>
2 Cr + 12 H2O + 3 H2SO4 = [Cr(H2O)6]2(SO4)3 + 3 H2
S2O8{2-} + Cr{3+} + H2O = Cr2O7{2-} + HSO4{-} + H3O{+} =>
3 S2O8{2-} + 2 Cr{3+} + 15 H2O = Cr2O7{2-} + 6 HSO4{-} + 8 H3O{+}
CU(OH)2 = CU + H2O + O2 =>
2 CU(OH)2 = 2 CU + 2 H2O + O2
HNaO3 + HCl = NaCl + Cl2 + H2O =>
HNaO3 + 5 HCl = NaCl + 2 Cl2 + 3 H2O
H = H2 =>
2 H = H2
Na2CO3 + H2O = OH + Na + CO =>
Na2CO3 + 2 H2O = 4 OH + 2 Na + CO
Cu + NaNO3 + HCl = Cu(NO3)2 + NaCl + NO + H2O =>
3 Cu + 8 NaNO3 + 8 HCl = 3 Cu(NO3)2 + 8 NaCl + 2 NO + 4 H2O
K3[Co(CN)6] + CoSO4 = Co3[Co(CN)6]2 + K2SO4 =>
2 K3[Co(CN)6] + 3 CoSO4 = Co3[Co(CN)6]2 + 3 K2SO4
Be + HBr = BeBr2 + H2 =>
Be + 2 HBr = BeBr2 + H2
Br2O7 + H2O = Br(OH)7 =>
Br2O7 + 7 H2O = 2 Br(OH)7
LiOH(aq) + HBr(aq) = LiBr(aq) + H2O =>
LiOH(aq) + HBr(aq) = LiBr(aq) + H2O
AlF3 + Br2 = AlBr3 + F2 =>
2 AlF3 + 3 Br2 = 2 AlBr3 + 3 F2
FeCl3(aq) + CuSO4(aq) = Fe2(SO4)3(aq) + CuCl2(aq) =>
2 FeCl3(aq) + 3 CuSO4(aq) = Fe2(SO4)3(aq) + 3 CuCl2(aq)
NaNO3 + K + HCl = NaCl + KNO3 + NO + H2O =>
4 NaNO3 + 3 K + 4 HCl = 4 NaCl + 3 KNO3 + NO + 2 H2O
C4H9SO3H + O2 = CO2 + H2O + SO2 =>
C4H9SO3H + 6 O2 = 4 CO2 + 5 H2O + SO2
CO(NH2)2 + H2SO4 + H2O = SO4(NH4)2 + CO2 =>
CO(NH2)2 + H2SO4 + H2O = SO4(NH4)2 + CO2
Cl2(aq) + KI(s) = KCl(aq) + I2(s) =>
Cl2(aq) + 2 KI(s) = 2 KCl(aq) + I2(s)
H2S + H3PO4 = H2SO4 + P + H2O =>
5 H2S + 8 H3PO4 = 5 H2SO4 + 8 P + 12 H2O
La(NO{3}){3} + NaOH = La + (OH){3} + NaNO{3} =>
La(NO{3}){3} + NaOH = La + (OH){3} + NaNO{3}
FeSO4 + NH4OH + H2O2 = Fe(OH)3 + (NH4)2SO4 =>
2 FeSO4 + 4 NH4OH + H2O2 = 2 Fe(OH)3 + 2(NH4)2SO4
H2 + Fe2 = HFe =>
H2 + Fe2 = 2 HFe
NaPO4 + ZnCl2 = ZnPO4 + NaCl2 =>
NaPO4 + ZnCl2 = ZnPO4 + NaCl2
Na2CO3 + Br2 = NaBr + NaBrO3 + CO2 =>
3 Na2CO3 + 3 Br2 = 5 NaBr + NaBrO3 + 3 CO2
Al + H2SO4 = Al2(SO4)3 + (H2)3 =>
2 Al + 3 H2SO4 = Al2(SO4)3 + (H2)3
NaHCO3(s) + HCl(aq) = CO2(g) + H2O(g) + NaCl(aq) =>
NaHCO3(s) + HCl(aq) = CO2(g) + H2O(g) + NaCl(aq)
AlH3Po4 = AlPo4H3 =>
AlH3Po4 = AlPo4H3
NH4Cl(aq) + NaOH(aq) = NH3(g) + NaCl(aq) + H2O(l) =>
NH4Cl(aq) + NaOH(aq) = NH3(g) + NaCl(aq) + H2O(l)
SnOHCl + H2SO4 = HCl + SnSO4 + H2O =>
SnOHCl + H2SO4 = HCl + SnSO4 + H2O
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 06/09/24
Equations balanced on 07/09/23
Please let us know how we can improve this web app.