Equations balanced on the previous day | Equations balanced on the next day |
Ba3(PO4)2 + 6 CH3COOH = 3 Ba(CH3COO)2 + 2 H3PO4
Ba3(PO4)2 + CH3COOH = Ba(H2PO4)2 + Ba(CH3COO)2 =>
Ba3(PO4)2 + 4 CH3COOH = Ba(H2PO4)2 + 2 Ba(CH3COO)2
C2H4(g) + O2(g) = CO(g) + H2O(g) =>
C2H4(g) + 2 O2(g) = 2 CO(g) + 2 H2O(g)
C2H4(g) + O2(g) = CO(g) + H2O(g) =>
C2H4(g) + 2 O2(g) = 2 CO(g) + 2 H2O(g)
K2CrO4(aq) + CaCl2(aq) = KCl(aq) + CaCrO4(aq) =>
K2CrO4(aq) + CaCl2(aq) = 2 KCl(aq) + CaCrO4(aq)
CaCl2(aq) + K2CrO4(aq) = CaCrO4 + KCl =>
CaCl2(aq) + K2CrO4(aq) = CaCrO4 + 2 KCl
C2H4(g) + O2(g) = CO(g) + H2O(g) =>
C2H4(g) + 2 O2(g) = 2 CO(g) + 2 H2O(g)
C2H4(g) + O2(g) = CO(g) + H2O(g) =>
C2H4(g) + 2 O2(g) = 2 CO(g) + 2 H2O(g)
CaCO3 + HCH3COO = H2O + CO2 + Ca(CH3COO) =>
8 CaCO3 + 9 HCH3COO = 6 H2O + 10 CO2 + 8 Ca(CH3COO)
C2H4(g) + O2(g) = CO(g) + H2O(g) =>
C2H4(g) + 2 O2(g) = 2 CO(g) + 2 H2O(g)
C2H4(g) + O2(g) = CO(g) + H2O(g) =>
C2H4(g) + 2 O2(g) = 2 CO(g) + 2 H2O(g)
CaCl2(aq) + K2CrO4(aq) = CaCrO4(s) + KCl(aq) =>
CaCl2(aq) + K2CrO4(aq) = CaCrO4(s) + 2 KCl(aq)
CaCO3 + HCH3COO = Ca(CH3COO)2 + H2CO3 =>
CaCO3 + 2 HCH3COO = Ca(CH3COO)2 + H2CO3
Mn(OH)2 + H2SO3 = Mn2(SO3)2 + H2O =>
2 Mn(OH)2 + 2 H2SO3 = Mn2(SO3)2 + 4 H2O
Ba3(PO4)2 + CH3COOH = (CH3COO)2Ba + H3PO4 =>
Ba3(PO4)2 + 6 CH3COOH = 3(CH3COO)2Ba + 2 H3PO4
C2H4(g) + O2(g) = CO(g) + H2O(g) =>
C2H4(g) + 2 O2(g) = 2 CO(g) + 2 H2O(g)
Cr2(SO4)3 + Mg(OH)2 = Mg(SO4) + Cr(OH)3 =>
Cr2(SO4)3 + 3 Mg(OH)2 = 3 Mg(SO4) + 2 Cr(OH)3
C2H4(g) + O2(g) = CO(g) + H2O(g) =>
C2H4(g) + 2 O2(g) = 2 CO(g) + 2 H2O(g)
NO2 + CaO = Ca(NO2)3 + Ca(NO3)2 =>
5 NO2 + 2 CaO = Ca(NO2)3 + Ca(NO3)2
Ba3(PO4)2 + CH3COOH = Ba(H2PO4)2 + Ba(CH3COO)2 =>
Ba3(PO4)2 + 4 CH3COOH = Ba(H2PO4)2 + 2 Ba(CH3COO)2
K2CrO4(aq) + CaCl2(aq) = KCl(aq) + CaCrO4(aq) =>
K2CrO4(aq) + CaCl2(aq) = 2 KCl(aq) + CaCrO4(aq)
BaNO3{2} + KI = BaI{2} + KNO3 =>
BaNO3{2} + KI = BaI{2} + KNO3
CaCO3 + HCH3COO = Ca(CH3COO)2 + H2CO3 =>
CaCO3 + 2 HCH3COO = Ca(CH3COO)2 + H2CO3
CaCO3 + HCH3COO = Ca(CH3COO)2 + H2CO3 =>
CaCO3 + 2 HCH3COO = Ca(CH3COO)2 + H2CO3
CaCO3 + HCH3COO = Ca(CH3COO)2 + H2CO3 =>
CaCO3 + 2 HCH3COO = Ca(CH3COO)2 + H2CO3
Ba3(PO4)2 + CH3COOH = Ba(H2PO4)2 + Ba(CH3COO)2 =>
Ba3(PO4)2 + 4 CH3COOH = Ba(H2PO4)2 + 2 Ba(CH3COO)2
CaCl2(aq) + K2CrO4(aq) = CaCrO4 + KCl =>
CaCl2(aq) + K2CrO4(aq) = CaCrO4 + 2 KCl
CaCl2(aq) + K2CrO4(aq) = CaCrO4 + KCl =>
CaCl2(aq) + K2CrO4(aq) = CaCrO4 + 2 KCl
Ba3(PO4)2 + CH3COOH = Ba(H2PO4)2 + Ba(CH3COO)2 =>
Ba3(PO4)2 + 4 CH3COOH = Ba(H2PO4)2 + 2 Ba(CH3COO)2
Ba3(PO4)2 + CH3COOH = Ba(H2PO4)2 + Ba(CH3COO)2 =>
Ba3(PO4)2 + 4 CH3COOH = Ba(H2PO4)2 + 2 Ba(CH3COO)2
CaCl2(aq) + K2CrO4(aq) = CaCrO4 + KCl =>
CaCl2(aq) + K2CrO4(aq) = CaCrO4 + 2 KCl
Ba3(PO4)2 + CH3COOH = Ba(H2PO4)2 + Ba(CH3COO)2 =>
Ba3(PO4)2 + 4 CH3COOH = Ba(H2PO4)2 + 2 Ba(CH3COO)2
CaCO3 + HCH3COO = Ca(CH3COO)2 + H2CO3 =>
CaCO3 + 2 HCH3COO = Ca(CH3COO)2 + H2CO3
CaCl2(aq) + K2CrO4(aq) = CaCrO4 + KCl =>
CaCl2(aq) + K2CrO4(aq) = CaCrO4 + 2 KCl
NaClO + H2SO4 = Na2SO4 + Cl2 + H2O2 =>
2 NaClO + H2SO4 = Na2SO4 + Cl2 + H2O2
CaCO3 + HCH3COO = Ca(CH3COO)2 + H2CO3 =>
CaCO3 + 2 HCH3COO = Ca(CH3COO)2 + H2CO3
Ce3{+} + Na{+} + BiO{+} + H2O = Ce4{+} + NaBiO3 + H{+} =>
8 Ce3{+} + Na{+} + BiO{+} + 2 H2O = 6 Ce4{+} + NaBiO3 + 4 H{+}
Rb + Mg3(BO3)2 = Rb3BO3 + Mg =>
6 Rb + Mg3(BO3)2 = 2 Rb3BO3 + 3 Mg
ZnS + H2SO4 = ZnSO4 + H2O + SO2 =>
ZnS + 4 H2SO4 = ZnSO4 + 4 H2O + 4 SO2
CaCO3 + HCH3COO = Ca(CH3COO)2 + H2CO3 =>
CaCO3 + 2 HCH3COO = Ca(CH3COO)2 + H2CO3
CaCO3 + HCH3COO = Ca(CH3COO)2 + H2CO3 =>
CaCO3 + 2 HCH3COO = Ca(CH3COO)2 + H2CO3
Ba3(PO4)2 + CH3COOH = Ba(H2PO4)2 + Ba(CH3COO)2 =>
Ba3(PO4)2 + 4 CH3COOH = Ba(H2PO4)2 + 2 Ba(CH3COO)2
K2CrO4(aq) + CaCl2(aq) = KCl(aq) + CaCrO4(aq) =>
K2CrO4(aq) + CaCl2(aq) = 2 KCl(aq) + CaCrO4(aq)
CaCO3 + HCH3COO = Ca(CH3COO)2 + H2CO3 =>
CaCO3 + 2 HCH3COO = Ca(CH3COO)2 + H2CO3
CaCl2(aq) + K2CrO4(aq) = CaCrO4 + KCl =>
CaCl2(aq) + K2CrO4(aq) = CaCrO4 + 2 KCl
CaCl2(aq) + K2CrO4(aq) = CaCrO4 + KCl =>
CaCl2(aq) + K2CrO4(aq) = CaCrO4 + 2 KCl
K2CrO4(aq) + CaCl2(aq) = KCl(aq) + CaCrO4(aq) =>
K2CrO4(aq) + CaCl2(aq) = 2 KCl(aq) + CaCrO4(aq)
CaCl2(aq) + K2CrO4(aq) = CaCrO4 + KCl =>
CaCl2(aq) + K2CrO4(aq) = CaCrO4 + 2 KCl
Ba3(PO4)2 + CH3COOH = Ba(H2PO4)2 + Ba(CH3COO)2 =>
Ba3(PO4)2 + 4 CH3COOH = Ba(H2PO4)2 + 2 Ba(CH3COO)2
K2CrO4(aq) + CaCl2(aq) = KCl(aq) + CaCrO4(aq) =>
K2CrO4(aq) + CaCl2(aq) = 2 KCl(aq) + CaCrO4(aq)
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 05/16/24
Equations balanced on 06/15/23
Please let us know how we can improve this web app.