Equations balanced on the previous day | Equations balanced on the next day |
CaS(aq)NiCl2(aq) = NiS(s)CaCl2(aq)
NaHCO3 + CuCl2 = CO2 + CuCO3 + H2O + NaCl =>
2 NaHCO3 + CuCl2 = CO2 + CuCO3 + H2O + 2 NaCl
C7H6O3 + C4H6O3 = C9H8O4 + C2H4O2 =>
C7H6O3 + C4H6O3 = C9H8O4 + C2H4O2
{-}Ghlor{-}2{-}methylpropanreagiertmitHydroxidionen = {-}Methvloropan{-}2{-}ol =>
{-}Ghlor{-}2{-}methylpropanreagiertmitHydroxidionen = {-}Methvloropan{-}2{-}ol
(Al(SO4)) + (BaCl) = (AlCl) + (Ba(SO4)) =>
(Al(SO4)) + (BaCl) = (AlCl) + (Ba(SO4))
HCO3H = H2OCO2 =>
HCO3H = H2OCO2
CH3 + Br2 = CH3Br2 =>
CH3 + Br2 = CH3Br2
*Zr(IO3)4*KIO3*8H2O + KI + HCl = I2 + H2O + ZrCl4 + KCl =>
*Zr(IO3)4*KIO3*8H2O + 25 KI + 30 HCl = 15 I2 + 23 H2O + ZrCl4 + 26 KCl
Cr2O7{-2} + H{+} + {-} = Cr{+3} + H2O =>
Cr2O7{-2} + 14 H{+} + 6e = 2 Cr{+3} + 7 H2O
[Cr(N2H2CO)6]4[Cr(CN)6]3 + MnO4{-} + H{+} = Cr2O7{-2} + CO2 + Mn{+2} + NO3{-} + H2O =>
2[Cr(N2H2CO)6]4[Cr(CN)6]3 + 216 MnO4{-} + 502 H{+} = 7 Cr2O7{-2} + 84 CO2 + 216 Mn{+2} + 132 NO3{-} + 299 H2O
C6H18O(g) + O2(g) = CO2(g) + H2O(l) =>
C6H18O(g) + 10 O2(g) = 6 CO2(g) + 9 H2O(l)
NaOH(aq)CuSo4(aq) = NaSo4(aq)CuOH(aq) =>
NaOH(aq)CuSo4(aq) = NaSo4(aq)CuOH(aq)
C4H9Br + C9H16N2 = (C7H14)2 + Br + N2 =>
28 C4H9Br + 14 C9H16N2 = 17(C7H14)2 + 28 Br + 14 N2
NaCH3COO(aq)AgNO3(aq) = NaNO3AgCH3COO =>
NaCH3COO(aq)AgNO3(aq) = NaNO3AgCH3COO
Al2(SO4)3 + H2SO4 = Al(HSO4)3 =>
Al2(SO4)3 + 3 H2SO4 = 2 Al(HSO4)3
Na3AsO4NH4ClMgSO4 = NH4MgAsO4NaClNa2SO4 =>
Na3AsO4NH4ClMgSO4 = NH4MgAsO4NaClNa2SO4
N{2}O{5} = N{2}O{4}O{2} =>
N{2}O{5} = N{2}O{4}O{2}
KOH + H2SO4 = K2SO4 + H2O =>
2 KOH + H2SO4 = K2SO4 + 2 H2O
AlCl3 + K3[Fe(Cn)6] = Al[Fe(Cn)6] + KCl =>
AlCl3 + K3[Fe(Cn)6] = Al[Fe(Cn)6] + 3 KCl
CuSo4(aq)Fe(s) = Fe(So4)(aq)Cu(s) =>
CuSo4(aq)Fe(s) = Fe(So4)(aq)Cu(s)
HNO3 + Fe(OH)2 + Cu(OH)2 = FeCu(NO3)4 + H2O =>
4 HNO3 + Fe(OH)2 + Cu(OH)2 = FeCu(NO3)4 + 4 H2O
Ca(OH)2 + Ba(ClO3)2 = Ca(ClO3)2 + Ba(OH)2 =>
Ca(OH)2 + Ba(ClO3)2 = Ca(ClO3)2 + Ba(OH)2
C3H6O2 + H2O2 = H2O + CO2 =>
C3H6O2 + 7 H2O2 = 10 H2O + 3 CO2
BaCl + Fe(SO4)3 = FeSO4 + Cl2 + BaSO4 =>
2 BaCl + Fe(SO4)3 = FeSO4 + Cl2 + 2 BaSO4
S + H2O = H2 + SOH =>
2 S + 2 H2O = H2 + 2 SOH
CaSO4 + Na2CO3 = CaCO3 + Na2SO4 =>
CaSO4 + Na2CO3 = CaCO3 + Na2SO4
Cl2(g)MgBr2(aq) = Br2(l)MgCl2(aq) =>
Cl2(g)MgBr2(aq) = Br2(l)MgCl2(aq)
NaHCO3(s)HCl(aq) = NaClCO2(g)H2O(g) =>
NaHCO3(s)HCl(aq) = NaClCO2(g)H2O(g)
Fe2 + Cu(SO4)2 = Fe(SO4)2 + Cu2 =>
Fe2 + 2 Cu(SO4)2 = 2 Fe(SO4)2 + Cu2
Na2S(aq) + Cu(NO3)2(aq) = NaNO3 + CuS(s) =>
Na2S(aq) + Cu(NO3)2(aq) = 2 NaNO3 + CuS(s)
Fe{2+} = e + Fe{3+} =>
Fe{2+} = e + Fe{3+}
Fe{2+} = e + Fe{3+} =>
Fe{2+} = e + Fe{3+}
C8H11N + Br2 = C8H11NBr =>
2 C8H11N + Br2 = 2 C8H11NBr
Hg + FeCl3 = HgCl2 + FeCl2 =>
Hg + 2 FeCl3 = HgCl2 + 2 FeCl2
C8H11N + Br2 = C8H11NBr =>
2 C8H11N + Br2 = 2 C8H11NBr
KIO3 + H2SO3 = H2O + H2SO4 + I2 + KHSO4 =>
2 KIO3 + 5 H2SO3 = H2O + 3 H2SO4 + I2 + 2 KHSO4
C2H6O2 + O2 = H2O + C2O =>
C2H6O2 + O2 = 3 H2O + C2O
ZnH2SO4(aq) = ZnSO4(aq)H2(g) =>
ZnH2SO4(aq) = ZnSO4(aq)H2(g)
Pr6O11 + HNO3 = Pr(NO3)3 + H2O + O2 =>
Pr6O11 + 18 HNO3 = 6 Pr(NO3)3 + 9 H2O + O2
C6H5CH2N(CH3)2CH3(CH2)15Br = CH3(CH2)15N(Br)(CH3)2CH2C6H5 =>
C6H5CH2N(CH3)2CH3(CH2)15Br = CH3(CH2)15N(Br)(CH3)2CH2C6H5
NaOH(aq)H2SO4(aq) = NaSO4(aq)H2OH =>
NaOH(aq)H2SO4(aq) = NaSO4(aq)H2OH
NH3N + O2 = N2O + H2O =>
4 NH3N + 5 O2 = 4 N2O + 6 H2O
Pr6O11 + HNO3 = Pr(NO3)3 + H2O + O2 =>
Pr6O11 + 18 HNO3 = 6 Pr(NO3)3 + 9 H2O + O2
C4H9NH2 + HNO3 = N2 + CO2 + H2O =>
5 C4H9NH2 + 27 HNO3 = 16 N2 + 20 CO2 + 41 H2O
Ca(OH)2 + H3PO4 = CaHPO4 + H2O =>
Ca(OH)2 + H3PO4 = CaHPO4 + 2 H2O
Pr6O11 + HNO3 = Pr(NO3)3 + H2 + O2 =>
2 Pr6O11 + 36 HNO3 = 12 Pr(NO3)3 + 18 H2 + 11 O2
C2H6 + Cl2 = CC4 + HCl =>
5 C2H6 + 15 Cl2 = 2 CC4 + 30 HCl
S + Cr2O3 = Cr3S3 + SO2 =>
21 S + 6 Cr2O3 = 4 Cr3S3 + 9 SO2
Ca(OH)2 + H3PO4 = HOH + Ca + PO4 =>
3 Ca(OH)2 + 2 H3PO4 = 6 HOH + 3 Ca + 2 PO4
Pb(NO3)2Cu(SO4) = Pb(SO4)Cu(NO3)2 =>
Pb(NO3)2Cu(SO4) = Pb(SO4)Cu(NO3)2
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 05/08/24
Equations balanced on 06/07/23
Please let us know how we can improve this web app.