Equations balanced on the previous day | Equations balanced on the next day |
CaCO3 + H2C2O4 = CaC2O4 + H2CO3
Ag + Br2 = AgBr =>
2 Ag + Br2 = 2 AgBr
KCl + Hg2(C2H3O2)2 = Hg2Cl2 + KC2H3O2 =>
2 KCl + Hg2(C2H3O2)2 = Hg2Cl2 + 2 KC2H3O2
K2S + Ni(NO3)2 = KNO3 + NiS =>
K2S + Ni(NO3)2 = 2 KNO3 + NiS
SodiumCarbonateHydrogenNitrate = SodiumNitrateHydrogenCarbonate =>
SodiumCarbonateHydrogenNitrate = SodiumNitrateHydrogenCarbonate
ZnSO4 + NH3 + H2O = [Zn(NH3)4](OH)2 + (NH4)2SO4 =>
ZnSO4 + 6 NH3 + 2 H2O = [Zn(NH3)4](OH)2 + (NH4)2SO4
H2 + O2 = H2O =>
2 H2 + O2 = 2 H2O
Mg(OH)2 + HF = MgF2 + H2O =>
Mg(OH)2 + 2 HF = MgF2 + 2 H2O
AgNO3(aq) + NaHCO3(aq) = AgHCO3(aq) + NaNO3(aq) =>
AgNO3(aq) + NaHCO3(aq) = AgHCO3(aq) + NaNO3(aq)
Al + CuCl = AlCl + Cu =>
Al + CuCl = AlCl + Cu
N(SiH3)2 + H2NSiH3 = N(SiH3)3 + HN =>
4 N(SiH3)2 + H2NSiH3 = 3 N(SiH3)3 + 2 HN
Li200S100 + Sn100S200 + Sb200S300 + S100 = Li385Sn085Sb15S400 =>
77 Li200S100 + 34 Sn100S200 + 3 Sb200S300 + 6 S100 = 40 Li385Sn085Sb15S400
Ag + Br2 = AgBr =>
2 Ag + Br2 = 2 AgBr
C21H23NO5 + O2 = CO2 + H2O + N2 =>
4 C21H23NO5 + 97 O2 = 84 CO2 + 46 H2O + 2 N2
Ca(OH)2 + NH4Cl = NH4OH + CaCl2 =>
Ca(OH)2 + 2 NH4Cl = 2 NH4OH + CaCl2
FeO3 + CO = Fe1 + CO2 =>
FeO3 + 3 CO = Fe1 + 3 CO2
AlBr3 + K2SO4 = KBr + Al2(SO4)3 =>
2 AlBr3 + 3 K2SO4 = 6 KBr + Al2(SO4)3
Ca(OH)2 + NaCl = CaCl2 + NaOH =>
Ca(OH)2 + 2 NaCl = CaCl2 + 2 NaOH
PCl3(l) + H2O(l) = H3PO3(aq) + HCl(aq) =>
PCl3(l) + 3 H2O(l) = H3PO3(aq) + 3 HCl(aq)
(CH3)3CH + O2 = CO2 + H2O =>
2(CH3)3CH + 13 O2 = 8 CO2 + 10 H2O
H8C6O6 + OH = H7C6O6 + H2O =>
H8C6O6 + OH = H7C6O6 + H2O
FeBr3 + K2CO3 + H2O = Fe(OH)3 + KBr + H2CO3 =>
2 FeBr3 + 3 K2CO3 + 6 H2O = 2 Fe(OH)3 + 6 KBr + 3 H2CO3
K2Cr2O7 + HCl + CH3CHO = KCl + CrCl3 + CH3COOH + H2O =>
K2Cr2O7 + 8 HCl + 3 CH3CHO = 2 KCl + 2 CrCl3 + 3 CH3COOH + 4 H2O
C14H18N2O5 + O2 = CO2 + H2O + N =>
C14H18N2O5 + 16 O2 = 14 CO2 + 9 H2O + 2 N
Ca3(PO4)2 + SiO2 + C = CO2 + Ca2O4Si + P4 =>
2 Ca3(PO4)2 + 3 SiO2 + 5 C = 5 CO2 + 3 Ca2O4Si + P4
Cu2Co3OH2 + HCo2H + H2O = CuCo2H2*4H2O + Co2 =>
2 Cu2Co3OH2 + 4 HCo2H + 14 H2O = 4 CuCo2H2*4H2O + 3 Co2
(NH4)3PO4 + Zn(NO3)2 = NH4NO3 + Zn3(PO4)2 =>
2(NH4)3PO4 + 3 Zn(NO3)2 = 6 NH4NO3 + Zn3(PO4)2
AuCl3 + NaHSO3 + H2O = Au + HCl + NaHSO4 =>
2 AuCl3 + 3 NaHSO3 + 3 H2O = 2 Au + 6 HCl + 3 NaHSO4
Pb(CH3COO)2 + KOH = Pb(OH)2 + KCH3COO =>
Pb(CH3COO)2 + 2 KOH = Pb(OH)2 + 2 KCH3COO
Cu(NO3)*2 + KOH = Cu(OH)*2 + KNO3 =>
Cu(NO3)*2 + KOH = Cu(OH)*2 + KNO3
Cu(ClO4)2 + Mg(C2H3O2)2 = Cu(C2H3O2)2 + Mg(ClO4)2 =>
Cu(ClO4)2 + Mg(C2H3O2)2 = Cu(C2H3O2)2 + Mg(ClO4)2
FeSO4 + KMnO4 + H2SO4 = Fe2(SO4)3 + MnSO4 + K2SO4 + H2O =>
10 FeSO4 + 2 KMnO4 + 8 H2SO4 = 5 Fe2(SO4)3 + 2 MnSO4 + K2SO4 + 8 H2O
SodiumCarbonateAmmoniumChloride = SodiumChlorideAmmoniumCarbonate =>
SodiumCarbonateAmmoniumChloride = SodiumChlorideAmmoniumCarbonate
CuO + NH4OH = [Cu(NH3)4](OH)2 + H2O =>
CuO + 4 NH4OH = [Cu(NH3)4](OH)2 + 3 H2O
NaOH(s) + H3PO4(aq) = Na3PO4(aq) + H2O =>
3 NaOH(s) + H3PO4(aq) = Na3PO4(aq) + 3 H2O
P + AgNO3 + H2O = Ag3P + H3PO4 + HNO3 =>
8 P + 15 AgNO3 + 12 H2O = 5 Ag3P + 3 H3PO4 + 15 HNO3
KOH + H2Po4 = K2Po4 + H2O =>
2 KOH + H2Po4 = K2Po4 + 2 H2O
Na + O2 = Na2O =>
4 Na + O2 = 2 Na2O
Sr2 + AgCl = SrCl2 + Ag =>
Sr2 + 4 AgCl = 2 SrCl2 + 4 Ag
C3H8 + O2 = CO2 + H2O =>
C3H8 + 5 O2 = 3 CO2 + 4 H2O
C4H10S(l) + O2(g) = CO2 + H2O + S =>
2 C4H10S(l) + 13 O2(g) = 8 CO2 + 10 H2O + 2 S
BrO3H + NaOH = BrO3Na + H2O =>
BrO3H + NaOH = BrO3Na + H2O
Be + H2 = BeH2 =>
Be + H2 = BeH2
H2NCI + NH3 = NH4CI + NH2 =>
H2NCI + 2 NH3 = NH4CI + 2 NH2
Zn + H3PO4 = Zn3(PO4)2 + H2 =>
3 Zn + 2 H3PO4 = Zn3(PO4)2 + 3 H2
KOH + H3PO4 = K3PO4 + H2O =>
3 KOH + H3PO4 = K3PO4 + 3 H2O
HAlO2 + NaOH = NaAlO2 + H2O =>
HAlO2 + NaOH = NaAlO2 + H2O
AuFe = FeAu =>
AuFe = FeAu
Cu(NO3)2 + Al = CuAl2 + NO3 =>
Cu(NO3)2 + 2 Al = CuAl2 + 2 NO3
Fe + Br2 + Na2Co3 + H2O = NaBr + Fe(OH)3 + HCo3 =>
Fe + 3 Br2 + 3 Na2Co3 + 3 H2O = 6 NaBr + Fe(OH)3 + 3 HCo3
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 04/02/24
Equations balanced on 05/02/23
Please let us know how we can improve this web app.