Equations balanced on the previous day | Equations balanced on the next day |
Al2O + C + 3 Cl2 = 2 AlCl3 + CO
H2SeO3 + Cl2 + H2O = H2SeO4 + HCl =>
H2SeO3 + Cl2 + H2O = H2SeO4 + 2 HCl
In(AcAc)3 + HNO3 = In(NO3)3 + H(AcAc)3 + NO + H2O =>
3 In(AcAc)3 + 11 HNO3 = 3 In(NO3)3 + 3 H(AcAc)3 + 2 NO + 4 H2O
MnO2(s) = Mn2O3(s) + O2(g) =>
4 MnO2(s) = 2 Mn2O3(s) + O2(g)
CHOOH + Na2CO3 = CHOONa + H2O + CO2 =>
2 CHOOH + Na2CO3 = 2 CHOONa + H2O + CO2
Hg(ClO3)2 + Na2Cr2O7 = HgCr2O7(s) + NaCl + O2 =>
Hg(ClO3)2 + Na2Cr2O7 = HgCr2O7(s) + 2 NaCl + 3 O2
Pb(OH)2 + H2CO3 = Pb2(CO3)2 + H2O =>
2 Pb(OH)2 + 2 H2CO3 = Pb2(CO3)2 + 4 H2O
KMnO4(aq) + KI(aq) + H2SO4(aq) = MnSO4(aq) + K2SO4(aq) + H2O(l) + I2(s) =>
2 KMnO4(aq) + 10 KI(aq) + 8 H2SO4(aq) = 2 MnSO4(aq) + 6 K2SO4(aq) + 8 H2O(l) + 5 I2(s)
Hg(ClO3)2 + Na2Cr2O7 = Na(ClO3) + Hg(Cr2O7) =>
Hg(ClO3)2 + Na2Cr2O7 = 2 Na(ClO3) + Hg(Cr2O7)
KCl + FeSO4 = KSO4 + FeCl =>
KCl + FeSO4 = KSO4 + FeCl
Pb(OH)4 + HNO3 = Pb(NO3)4 + H2O =>
Pb(OH)4 + 4 HNO3 = Pb(NO3)4 + 4 H2O
MnO2 + ClO3{-} + OH{-} = MnO4{-} + Cl{-} + H2O =>
2 MnO2 + ClO3{-} + 2 OH{-} = 2 MnO4{-} + Cl{-} + H2O
KMnO4(aq) + KI(aq) + H2SO4(aq) = K2SO4(aq) + MnSO4(aq) + I2(aq) + H2O(l) =>
2 KMnO4(aq) + 10 KI(aq) + 8 H2SO4(aq) = 6 K2SO4(aq) + 2 MnSO4(aq) + 5 I2(aq) + 8 H2O(l)
Na2S(aq) + AlCl3(aq) = NaCl + Al2S3 =>
3 Na2S(aq) + 2 AlCl3(aq) = 6 NaCl + Al2S3
K + Fe(OH)3 = K(OH)3 + Fe =>
K + Fe(OH)3 = K(OH)3 + Fe
NaS + CuCl = NaCl + CuS =>
NaS + CuCl = NaCl + CuS
AlBr3 + Cl2 = AlCl2 + Br2 =>
2 AlBr3 + 2 Cl2 = 2 AlCl2 + 3 Br2
Al(Br)3 + KMnO7 + H2SO4 = Al2(SO4) + Mn(SO4) + K2(SO4) + Br + H2O =>
22 Al(Br)3 + 2 KMnO7 + 14 H2SO4 = 11 Al2(SO4) + 2 Mn(SO4) + K2(SO4) + 66 Br + 14 H2O
COSO4 + AlOH3 = COOH3 + SO4Al =>
COSO4 + AlOH3 = COOH3 + SO4Al
HNO3 + Na + CO3 = NaNO3 + H2O + CO2 =>
2 HNO3 + 2 Na + CO3 = 2 NaNO3 + H2O + CO2
C2H2O4 + H2O = CO2 + H3O{+} + e =>
C2H2O4 + 2 H2O = 2 CO2 + 2 H3O{+} + 2e
H2O + NaOH = NaH3 + O =>
H2O + NaOH = NaH3 + 2 O
Na + P = Na3P3 =>
3 Na + 3 P = Na3P3
CaC12H22O14 + K(OH) = Ca(OH)2 + K2C12H22O14 =>
CaC12H22O14 + 2 K(OH) = Ca(OH)2 + K2C12H22O14
CrCl3 + Cl2 + KOH = K2CrO4 + KCl + H2O =>
2 CrCl3 + 3 Cl2 + 16 KOH = 2 K2CrO4 + 12 KCl + 8 H2O
FeCl3 + Na2S + H2O = NaCl + Fe(OH)2 + H2S + SO2 =>
6 FeCl3 + 9 Na2S + 14 H2O = 18 NaCl + 6 Fe(OH)2 + 8 H2S + SO2
H3PO4 + KOH = K3PO4 + H2O =>
H3PO4 + 3 KOH = K3PO4 + 3 H2O
Pb + NaCl = PbCl2 + Na =>
Pb + 2 NaCl = PbCl2 + 2 Na
BrO3 + KBr + HCl = Br2 + KCl + H2O =>
2 BrO3 + 12 KBr + 12 HCl = 7 Br2 + 12 KCl + 6 H2O
[Co(NH3)6] + H2O = [Co(NH3)5(H2O)] + NH3 =>
[Co(NH3)6] + H2O = [Co(NH3)5(H2O)] + NH3
C5H14 + Cl2 = C6H13Cl + HCl =>
6 C5H14 + 12 Cl2 = 5 C6H13Cl + 19 HCl
KCl + Br = KBr + Cl2 =>
2 KCl + 2 Br = 2 KBr + Cl2
MgO + CuCl = CuO + MgCl =>
MgO + CuCl = CuO + MgCl
BCl3 + NF3 = BCl3NF3 =>
BCl3 + NF3 = BCl3NF3
Cl2(CHCl3) + KI = KCl + I2(CHCl3) =>
Cl2(CHCl3) + 2 KI = 2 KCl + I2(CHCl3)
N2H4 + Cu(OH)2 = N2 + Cu + H2O =>
N2H4 + 2 Cu(OH)2 = N2 + 2 Cu + 4 H2O
SiF4 + H2O = HF + SiO2 =>
SiF4 + 2 H2O = 4 HF + SiO2
Na2S + Hg + H2O = Na + H2S + Hg(OH)2 =>
Na2S + Hg + 2 H2O = 2 Na + H2S + Hg(OH)2
H(NO3) + NH4(OH) = NH4(NO3) + H2O =>
H(NO3) + NH4(OH) = NH4(NO3) + H2O
C9H18O2 + NaOH = C2H4O2 + C7H14OH + Na =>
C9H18O2 + NaOH = C2H4O2 + C7H14OH + Na
K2SO4(aq) + BaCl2(aq) = BaSO4(s) + KCl(aq) =>
K2SO4(aq) + BaCl2(aq) = BaSO4(s) + 2 KCl(aq)
KClO + KI + H2O = KCl + I2 + KOH =>
KClO + 2 KI + H2O = KCl + I2 + 2 KOH
FeCl3 + H2S = HCl + Fe2S3 = HCl =>
2 FeCl3 + 3 H2S = 6 HCl + Fe2S3
N2 + CaCl2 = Ca3N2 + Cl =>
N2 + 3 CaCl2 = Ca3N2 + 6 Cl
(NH4)SO4 + NaI = (NH4)I + SO4Na =>
(NH4)SO4 + NaI = (NH4)I + SO4Na
NH3 + H2O2 = H2O + HNO2 =>
NH3 + 3 H2O2 = 4 H2O + HNO2
SiO2 + XeF6 = XeOF4 + SiF4 =>
SiO2 + 2 XeF6 = 2 XeOF4 + SiF4
P2O3 + Ca(OH)2 = Ca3(PO3)2 + H2O =>
P2O3 + 3 Ca(OH)2 = Ca3(PO3)2 + 3 H2O
HgSO4 + Al = HgAl + SO4 =>
HgSO4 + Al = HgAl + SO4
C6H5COOH + O2 = CO2 + H2O =>
2 C6H5COOH + 15 O2 = 14 CO2 + 6 H2O
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 01/12/24
Equations balanced on 02/11/23
Please let us know how we can improve this web app.