Equations balanced on the previous day | Equations balanced on the next day |
381160593 Fe27O + 1720252647 U31 = 935576001 Fe11U57 + 341 O1117773
H3AsO4 + Mn(OH)3 = MnAsO4 + H2O =>
H3AsO4 + Mn(OH)3 = MnAsO4 + 3 H2O
CaCo3 + Li3PO4 = Li2Co3 + Ca3(PO4)2 =>
3 CaCo3 + 2 Li3PO4 = 3 Li2Co3 + Ca3(PO4)2
HNO3 + Fe = Fe(NO3)2 + H2O + NO2 =>
4 HNO3 + Fe = Fe(NO3)2 + 2 H2O + 2 NO2
HNO3 + Fe = Fe(NO3)2 + H2O + NO2 =>
4 HNO3 + Fe = Fe(NO3)2 + 2 H2O + 2 NO2
KBrO3 + Cu + HSO4 = Br2 + CuSO4 + K2SO4 + H2O =>
2 KBrO3 + 11 Cu + 12 HSO4 = Br2 + 11 CuSO4 + K2SO4 + 6 H2O
HCl + CdO = CdCl2 + H2O =>
2 HCl + CdO = CdCl2 + H2O
C6H12O6 = C2H5OH + CO2 =>
C6H12O6 = 2 C2H5OH + 2 CO2
HClO + Ni(OH)3 = Ni(ClO)3 + H2O =>
3 HClO + Ni(OH)3 = Ni(ClO)3 + 3 H2O
KMnO4 + H2SO4 + H2C2O3 = K2SO4 + MnSO4 + CO2 + H2O =>
4 KMnO4 + 6 H2SO4 + 5 H2C2O3 = 2 K2SO4 + 4 MnSO4 + 10 CO2 + 11 H2O
Cr2(SO4)3 + (NH4)2(SO3) = Cr2(SO3)3 + (NH4)2SO4 =>
Cr2(SO4)3 + 3(NH4)2(SO3) = Cr2(SO3)3 + 3(NH4)2SO4
CrCl3 + NaClO3 + NaOH = Na2CrO4 + NaCl + H2O =>
2 CrCl3 + NaClO3 + 10 NaOH = 2 Na2CrO4 + 7 NaCl + 5 H2O
C2H5OH + HCOOH = C3H6O2 + H2 =>
4 C2H5OH + HCOOH = 3 C3H6O2 + 4 H2
NaNO3 + PbO = Pb(NO3)2 + Na2O =>
2 NaNO3 + PbO = Pb(NO3)2 + Na2O
HCO3 + Al(OH)3 = Al(CO3)3 + H2O =>
3 HCO3 + Al(OH)3 = Al(CO3)3 + 3 H2O
Fe27O + U31 = Fe11U57 + O1117773 =>
381160593 Fe27O + 1720252647 U31 = 935576001 Fe11U57 + 341 O1117773
Fe27O + U31 = Fe11U57 + O1117773 =>
381160593 Fe27O + 1720252647 U31 = 935576001 Fe11U57 + 341 O1117773
Co2 + H2O = Co2O3 + H2 =>
Co2 + 3 H2O = Co2O3 + 3 H2
HNO3 + Fe = Fe(NO3)2 + H2O + NO2 =>
4 HNO3 + Fe = Fe(NO3)2 + 2 H2O + 2 NO2
BaCl2 + Sb(NO3)3 = Ba(NO3)2 + SbCl3 =>
3 BaCl2 + 2 Sb(NO3)3 = 3 Ba(NO3)2 + 2 SbCl3
HNO3 + Fe = Fe(NO3)2 + H2O + NO2 =>
4 HNO3 + Fe = Fe(NO3)2 + 2 H2O + 2 NO2
La2O3 + W2O + O2 = La2W2O7 =>
2 La2O3 + 2 W2O + 3 O2 = 2 La2W2O7
CUCl2 + K3PO4 = K3Cl2 + CUPO4 =>
CUCl2 + K3PO4 = K3Cl2 + CUPO4
Al2(CO3)3 + CH3COOH = Al(CH3COO) + CO2 + H2O =>
2 Al2(CO3)3 + 5 CH3COOH = 4 Al(CH3COO) + 8 CO2 + 4 H2O
C17H35COOH + NaOH = C17H35COONa + OH + H =>
C17H35COOH + NaOH = C17H35COONa + OH + H
CaCH3O2 + AlBr3 = CaBr + Al(CH3O2)3 =>
3 CaCH3O2 + AlBr3 = 3 CaBr + Al(CH3O2)3
UO2 = (UO2) =>
UO2 = (UO2)
C2H4O2 + O2 = CO2 + H2O =>
C2H4O2 + 2 O2 = 2 CO2 + 2 H2O
CaCl2 + H3PO4 = Ca3(PO4)2 + H5Cl5 =>
15 CaCl2 + 10 H3PO4 = 5 Ca3(PO4)2 + 6 H5Cl5
Cu(NO3)2(aq) + NA(aq) = Cu + NANO3(aq) =>
Cu(NO3)2(aq) + 2 NA(aq) = Cu + 2 NANO3(aq)
HNO3 + Ca2CO3 = CaNO3 + CO2 + H2O =>
2 HNO3 + Ca2CO3 = 2 CaNO3 + CO2 + H2O
C17H35COOH + NaOH = C17H35COONa + OH + H =>
C17H35COOH + NaOH = C17H35COONa + OH + H
KOH + Sb2S3 = K2S + Sb2O3 + H2O =>
6 KOH + Sb2S3 = 3 K2S + Sb2O3 + 3 H2O
HCl + C = CCl4 + H =>
4 HCl + C = CCl4 + 4 H
HI + H2SO4 = H2O + H2S + (I)2 =>
8 HI + H2SO4 = 4 H2O + H2S + 4(I)2
C10H8O + C2H5Br + KOH = C12H12O + H2O + KBr =>
C10H8O + C2H5Br + KOH = C12H12O + H2O + KBr
C10H8O + C2H5Br + KOH = C12H12O + H2O + KBr =>
C10H8O + C2H5Br + KOH = C12H12O + H2O + KBr
Co(NO3)2 + HCl = CoCl4 + H4N2O6 =>
Co(NO3)2 + 4 HCl = CoCl4 + H4N2O6
H3PO4 + KOH = H4PO5K =>
H3PO4 + KOH = H4PO5K
C17H35COOH + NaOH = C17H35COONa + OH + H =>
C17H35COOH + NaOH = C17H35COONa + OH + H
CaCH3O2 + AlBr3 = CaBr + Al(CH3O2)3 =>
3 CaCH3O2 + AlBr3 = 3 CaBr + Al(CH3O2)3
HCOOH + K2S = HCOOK + H2S =>
2 HCOOH + K2S = 2 HCOOK + H2S
C10H8O + C2H5Br + KOH = C12H12O + H2O + KBr =>
C10H8O + C2H5Br + KOH = C12H12O + H2O + KBr
K2Cr2O7 + SnCl2 + HCl = CrCl3 + SnCl4 + KCl + H2O =>
K2Cr2O7 + 3 SnCl2 + 14 HCl = 2 CrCl3 + 3 SnCl4 + 2 KCl + 7 H2O
UO2 = (UO2) =>
UO2 = (UO2)
C8H18(aq) + O2(g) = CO2 + H2O =>
2 C8H18(aq) + 25 O2(g) = 16 CO2 + 18 H2O
C17H35COOH + NaOH = C17H35COONa + OH + H =>
C17H35COOH + NaOH = C17H35COONa + OH + H
As2O3 + HNO3 + H2O = NO2 + H3AsO4 =>
As2O3 + 4 HNO3 + H2O = 4 NO2 + 2 H3AsO4
C10H8O + C2H5Br + KOH = C12H12O + H2O + KBr =>
C10H8O + C2H5Br + KOH = C12H12O + H2O + KBr
HI + H2SO4 = H2O + H2S + (I)2 =>
8 HI + H2SO4 = 4 H2O + H2S + 4(I)2
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 01/04/24
Equations balanced on 02/03/23
Please let us know how we can improve this web app.