Equations balanced on the previous day | Equations balanced on the next day |
KAl(SO4)2*12H2O + 3 KOH = Al(OH)3 + 12 H2O + 4 K + 2 SO4
CaSO3 + H3PO4 + Al + H2O = Al2(SO4)3 + Ca3(PO4)2 + H2 =>
3 CaSO3 + 2 H3PO4 + 2 Al + 3 H2O = Al2(SO4)3 + Ca3(PO4)2 + 6 H2
Al(OH)3 + AnswerHCl = AlCl3 + AnswerH2O =>
Al(OH)3 + 3 AnswerHCl = AlCl3 + 3 AnswerH2O
H2S + O2 = HO + S =>
H2S + O2 = 2 HO + S
ZnO2 + Co(NO3)2 = Co(ZnO2) + NO2 + O2 =>
ZnO2 + Co(NO3)2 = Co(ZnO2) + 2 NO2 + O2
Na2S + FeCl3 = FeS + S + NaCl =>
3 Na2S + 2 FeCl3 = 2 FeS + S + 6 NaCl
KAlO2 + CO2 + H2O = Al(OH)3 + KHCO3 =>
KAlO2 + CO2 + 2 H2O = Al(OH)3 + KHCO3
C3H6O + H2O2 = H2O + C =>
C3H6O + 2 H2O2 = 5 H2O + 3 C
K + ZnCl2 = ClK + Zn =>
2 K + ZnCl2 = 2 ClK + Zn
(NH4)2C2O4 + KOH = NH3 + K2C2O4 + H2O =>
(NH4)2C2O4 + 2 KOH = 2 NH3 + K2C2O4 + 2 H2O
ZmCl2 + H2O = Zm(OH)2 + HCl =>
ZmCl2 + 2 H2O = Zm(OH)2 + 2 HCl
HCOOH + Na2CO3 = COOHNa + CO2 + H2O =>
2 HCOOH + Na2CO3 = 2 COOHNa + CO2 + H2O
CaCl + Na2Co3 = CaCo3 + Na2Cl =>
CaCl + Na2Co3 = CaCo3 + Na2Cl
K2CrO4 + (NH4)2S + KOH + H2O = K3[Cr(OH)6] + K2SO3 + NH3 =>
2 K2CrO4 + (NH4)2S + 4 KOH + 3 H2O = 2 K3[Cr(OH)6] + K2SO3 + 2 NH3
K(s) + Cl(g)2 = KCl =>
2 K(s) + Cl(g)2 = 2 KCl
Mg(s) + Ga(ClO4)3(aq) = Ga(s) + Mg(ClO4)2(aq) =>
3 Mg(s) + 2 Ga(ClO4)3(aq) = 2 Ga(s) + 3 Mg(ClO4)2(aq)
Zn(s) + HCl(aq) = ZnCl2(aq) + H2(g) =>
Zn(s) + 2 HCl(aq) = ZnCl2(aq) + H2(g)
FeS + HNO3 = Fe(NO3)3 + Fe2(SO4)3 + N2O + H2O =>
24 FeS + 78 HNO3 = 8 Fe(NO3)3 + 8 Fe2(SO4)3 + 27 N2O + 39 H2O
SrCO3 + CH3COOH = Sr(CH3COO)2 + CO2 + H2O =>
SrCO3 + 2 CH3COOH = Sr(CH3COO)2 + CO2 + H2O
HCl + In2O3 = H2O + InCl3 =>
6 HCl + In2O3 = 3 H2O + 2 InCl3
K + ZnCl2 = ClK + Zn =>
2 K + ZnCl2 = 2 ClK + Zn
NaCl + H2SO4 = NaHSO4 + HCl =>
NaCl + H2SO4 = NaHSO4 + HCl
Na3[Co(CO3)3] + [H3NCH2CH2NH3]Cl2 = [Co(H2NCH2CH2NH2)3]Cl3 + NaCl + CO2 + H2O =>
Na3[Co(CO3)3] + 3[H3NCH2CH2NH3]Cl2 = [Co(H2NCH2CH2NH2)3]Cl3 + 3 NaCl + 3 CO2 + 3 H2O
K + ZnCl2 = ClK + Zn =>
2 K + ZnCl2 = 2 ClK + Zn
K + ZnCl2 = ClK + Zn =>
2 K + ZnCl2 = 2 ClK + Zn
Fe(OH)2 + O2 + H2O = Fe(OH)3 =>
4 Fe(OH)2 + O2 + 2 H2O = 4 Fe(OH)3
C4H8 + KMnO4 + H2SO4 = HC2H3O2 + K2SO4 + MnSO4 + H2O =>
5 C4H8 + 8 KMnO4 + 12 H2SO4 = 10 HC2H3O2 + 4 K2SO4 + 8 MnSO4 + 12 H2O
BaCl2 + K3(PO4) = Ba3(PO4)2 + KCl =>
3 BaCl2 + 2 K3(PO4) = Ba3(PO4)2 + 6 KCl
Mn + Fe2O3 = Mn2O + Fe =>
6 Mn + Fe2O3 = 3 Mn2O + 2 Fe
Cu(s) + HNO3(aq) = NO2(g) + Cu(NO3)2(aq) + H2O =>
Cu(s) + 4 HNO3(aq) = 2 NO2(g) + Cu(NO3)2(aq) + 2 H2O
K + ZnCl2 = KCl + Zn =>
2 K + ZnCl2 = 2 KCl + Zn
K + ZnCl2 = ClK + Zn =>
2 K + ZnCl2 = 2 ClK + Zn
Si + H2O = SiO3 + H2 =>
Si + 3 H2O = SiO3 + 3 H2
XCuSO4 + NH4OH = XCu(OH)2 + (NH4)2SO4 =>
XCuSO4 + 2 NH4OH = XCu(OH)2 + (NH4)2SO4
H2O + F2 = HF + O2 =>
2 H2O + 2 F2 = 4 HF + O2
CuO + HCl = Cu3Cl6 + H2O =>
3 CuO + 6 HCl = Cu3Cl6 + 3 H2O
HClO2 + Fe(OH)2 = Fe(ClO2)2 + H2O =>
2 HClO2 + Fe(OH)2 = Fe(ClO2)2 + 2 H2O
K + ZnCl2 = ClK + Zn =>
2 K + ZnCl2 = 2 ClK + Zn
Li(s) + AlO(aq) = LiO(aq) + Al(s) =>
Li(s) + AlO(aq) = LiO(aq) + Al(s)
K + ZnCl2 = ClK + Zn =>
2 K + ZnCl2 = 2 ClK + Zn
KOH + CaPO4 = KPO4 + CaOH =>
KOH + CaPO4 = KPO4 + CaOH
Au(OH)3 + H2CO2 = Au2C3O6 + H2O =>
2 Au(OH)3 + 3 H2CO2 = Au2C3O6 + 6 H2O
IO3{-} + HSO3{-} + H2O = I{-} + SO4{-2} + H3O{+} =>
IO3{-} + 3 HSO3{-} + 3 H2O = I{-} + 3 SO4{-2} + 3 H3O{+}
AmmoniumSulfate + LithiumHydroxide = LithiumSulfate + AmmoniumHydroxide =>
(NH4)2SO4 + 2 LiOH = Li2SO4 + 2 NH4OH
Na2CO3(aq) + HCl(aq) = NaCl(aq)NaHCO3(aq) =>
Na2CO3(aq) + HCl(aq) = NaCl(aq)NaHCO3(aq)
HC2H3O2(aq) + NaHCO3(aq) = NaC2H3O2(aq) + H2CO3 =>
HC2H3O2(aq) + NaHCO3(aq) = NaC2H3O2(aq) + H2CO3
Ba(NO)2 + Na2SO4 = BaSO4 + NaNO =>
Ba(NO)2 + Na2SO4 = BaSO4 + 2 NaNO
HCl(aq) + NaHCO3(s) = H2CO3(s) + NaCl(aq) =>
HCl(aq) + NaHCO3(s) = H2CO3(s) + NaCl(aq)
Fe2(SO4)3 + KOH = K2SO4 + Fe(OH)3 =>
Fe2(SO4)3 + 6 KOH = 3 K2SO4 + 2 Fe(OH)3
Cr2O72{-} + Sc2{-} + H{+} = Cr3{+} + Sc + H2O =>
3 Cr2O72{-} + 427 Sc2{-} + 432 H{+} = 2 Cr3{+} + 854 Sc + 216 H2O
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 12/05/23
Equations balanced on 01/04/23
Please let us know how we can improve this web app.