Equations balanced on the previous day | Equations balanced on the next day |
C100H150O100N50 = 10 C6H15N + 40 C + 50 O2 + 20 N2
(C3H5) + O2 = CO2 + H2O =>
4(C3H5) + 17 O2 = 12 CO2 + 10 H2O
Al2(SO4)3 + HBr = Al(Br)3 + H2SO4 =>
Al2(SO4)3 + 6 HBr = 2 Al(Br)3 + 3 H2SO4
C6H12O6 + KMnO4 + NaOH = Na2CO3 + MnO2 + KOH + H2O =>
C6H12O6 + 8 KMnO4 + 12 NaOH = 6 Na2CO3 + 8 MnO2 + 8 KOH + 8 H2O
NH4{+} + O2 = H2O + NO3{-} + H{+} =>
NH4{+} + 2 O2 = H2O + NO3{-} + 2 H{+}
Zn3HCO2 + H3PO4 = Zn3PO2 + H2O + CO2 =>
Zn3HCO2 + H3PO4 = Zn3PO2 + 2 H2O + CO2
SO2 + H2O = H2SO3 = H2 + SO3 =>
SO2 + H2O = H2SO3
C6H14S + O2 = CO2 + H2O + SO2 =>
2 C6H14S + 21 O2 = 12 CO2 + 14 H2O + 2 SO2
CH3 + O2 = CH2 + H2O =>
4 CH3 + O2 = 4 CH2 + 2 H2O
As2S3(s) + OH{-} = AsO3{3-} + H2S =>
As2S3(s) + 6 OH{-} = 2 AsO3{3-} + 3 H2S
H2SO4 + NaOH = H2O + SO4 + Na =>
H2SO4 + 2 NaOH = 2 H2O + SO4 + 2 Na
NO3({-}) + H = NH3 + H2O + OH({-}) =>
NO3({-}) + 8 H = NH3 + 2 H2O + OH({-})
FeCl2 + HO + HCl = FeCl3*H2O =>
FeCl2 + HO + HCl = FeCl3*H2O
CuS + NH4OH + O2 = [Cu(NH3)4]SO4 + H2O =>
CuS + 4 NH4OH + 2 O2 = [Cu(NH3)4]SO4 + 4 H2O
H2O + SiO3{2-} + NO2{-} = Si + NO3{-} + OH{-} =>
H2O + SiO3{2-} + 2 NO2{-} = Si + 2 NO3{-} + 2 OH{-}
[Cu(NH3)]SO4(aq) = [Cu(NH3)] + (SO4) =>
[Cu(NH3)]SO4(aq) = [Cu(NH3)] + (SO4)
CH3CH2OH + H2O = CH3OH =>
CH3CH2OH + H2O = 2 CH3OH
Zn + CuCl2(aq) = ZnCl2 + Cu =>
Zn + CuCl2(aq) = ZnCl2 + Cu
CuO + H2 = Cu + H2O =>
CuO + H2 = Cu + H2O
Ca(BrO3)2 + HNO3 = Ca(NO3)2 + HBrO3 =>
Ca(BrO3)2 + 2 HNO3 = Ca(NO3)2 + 2 HBrO3
Zn + CuCl2(aq) = Cu + ZnCl2(aq) =>
Zn + CuCl2(aq) = Cu + ZnCl2(aq)
AgCl + KBr = AgBr + KCl =>
AgCl + KBr = AgBr + KCl
NaHCO3 + HCH2COOH = CO2 + H2O + NaC2H4O2 =>
8 NaHCO3 + 9 HCH2COOH = 10 CO2 + 6 H2O + 8 NaC2H4O2
H2CO3 = HCO3 + H =>
H2CO3 = HCO3 + H
CH4O = CH4 + CO2 + H2O =>
4 CH4O = 3 CH4 + CO2 + 2 H2O
Fe2(SO4)3 + H2CO3 = H2SO4 + Fe2(CO3)3 =>
Fe2(SO4)3 + 3 H2CO3 = 3 H2SO4 + Fe2(CO3)3
MgSO4(aq) + Ba(OH)2(aq) = Mg(OH)2 + Ba(SO4) =>
MgSO4(aq) + Ba(OH)2(aq) = Mg(OH)2 + Ba(SO4)
NH3 + CH3COOH = NH4OOCCH3 =>
NH3 + CH3COOH = NH4OOCCH3
C6H11OOH + NaOH = C6H11OONa + H2O =>
C6H11OOH + NaOH = C6H11OONa + H2O
Cl + H2O = HClO3 + H2 =>
2 Cl + 6 H2O = 2 HClO3 + 5 H2
Cu(NO3)2(aq) + K2CrO4(aq) = CuCrO4 + (NO3)2K2 =>
Cu(NO3)2(aq) + K2CrO4(aq) = CuCrO4 + (NO3)2K2
NaOH + (NH4)2SO4 = NH3 + Na2SO4 + H2O =>
2 NaOH + (NH4)2SO4 = 2 NH3 + Na2SO4 + 2 H2O
LiH + AlCl3 = LiAlH4 + LiCl =>
4 LiH + AlCl3 = LiAlH4 + 3 LiCl
CH3CH(OH)COOH + NaOH = CH3CH(OH)COO + H2O + Na =>
CH3CH(OH)COOH + NaOH = CH3CH(OH)COO + H2O + Na
Cr(NO3)3 + KOH + H2O2 = K2CrO4 + HNO3 + H2O =>
2 Cr(NO3)3 + 4 KOH + 3 H2O2 = 2 K2CrO4 + 6 HNO3 + 2 H2O
XCHCH2 + H2SO4 + KMnO4 = XCOOH + CO2 + H2O + K2SO4 + MnSO4 =>
XCHCH2 + 3 H2SO4 + 2 KMnO4 = XCOOH + CO2 + 4 H2O + K2SO4 + 2 MnSO4
NH4Cl + Al2(SO4)3 = AlCl3 + (NH4)2SO4 =>
6 NH4Cl + Al2(SO4)3 = 2 AlCl3 + 3(NH4)2SO4
MgO + SiO2 = MgSiO3 =>
MgO + SiO2 = MgSiO3
No(OH)2 + Cl2 + H2O = No(OH)3 + HCl =>
2 No(OH)2 + Cl2 + 2 H2O = 2 No(OH)3 + 2 HCl
Cu + O2 = Cu22O3 =>
44 Cu + 3 O2 = 2 Cu22O3
HNO3 + As2S5 = H3AsO4 + H2SO4 + NO2 + H2O =>
40 HNO3 + As2S5 = 2 H3AsO4 + 5 H2SO4 + 40 NO2 + 12 H2O
K2O2 + H2O = KOH + O2 =>
2 K2O2 + 2 H2O = 4 KOH + O2
HCl + NaOH = NaCl + H2O =>
HCl + NaOH = NaCl + H2O
H2O(l) + MnO4{-}(aq) + Sn{2+}(aq) = MnO2(s) + Sn{4+}(aq) + OH{-}(aq) =>
4 H2O(l) + 2 MnO4{-}(aq) + 3 Sn{2+}(aq) = 2 MnO2(s) + 3 Sn{4+}(aq) + 8 OH{-}(aq)
Fe(s) + CH3COOH(aq) = Fe(CH3COO)2(aq) + H2(g) =>
Fe(s) + 2 CH3COOH(aq) = Fe(CH3COO)2(aq) + H2(g)
KMnO4 + CH3CH2OH + NaOH = CH3COOH + H2O + K2MnO4 + NaMnO4 =>
8 KMnO4 + CH3CH2OH + 4 NaOH = CH3COOH + 3 H2O + 4 K2MnO4 + 4 NaMnO4
FeCl3(aq) + Cs3PO4(aq) = FePO4(s) + CsCl(aq) =>
FeCl3(aq) + Cs3PO4(aq) = FePO4(s) + 3 CsCl(aq)
MgO + SiO2 = MgSiO3 =>
MgO + SiO2 = MgSiO3
FeCr2O4 + K2CO3 + KClO3 = Fe2O3 + K2CrO4 + KCl + CO2 =>
6 FeCr2O4 + 12 K2CO3 + 7 KClO3 = 3 Fe2O3 + 12 K2CrO4 + 7 KCl + 12 CO2
C6H4 + H2O = C6H5OH =>
C6H4 + H2O = C6H5OH
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 12/03/23
Equations balanced on 01/02/23
Please let us know how we can improve this web app.