Equations balanced on the previous day | Equations balanced on the next day |
5 C2H4O + K2Cr2O7 + 2 H2SO4 = 5 C2H4O2 + K2SO4 + Cr2(SO4) + 2 H2O
Cr2O7{-2} + H{+} + {-} = Cr{+3} + H2O =>
Cr2O7{-2} + 14 H{+} + 6e = 2 Cr{+3} + 7 H2O
Zn + Cu2(SO4)2 = Cu + Zn2(SO4)22 =>
2 Zn + 11 Cu2(SO4)2 = 22 Cu + Zn2(SO4)22
Mg + CO2 = CO + MgO =>
Mg + CO2 = CO + MgO
H2SO3 + Be(OH)2 = Be(HSO3)2 + H2O =>
2 H2SO3 + Be(OH)2 = Be(HSO3)2 + 2 H2O
Li + H3(PO4) = Li3(PO4) + H2 =>
6 Li + 2 H3(PO4) = 2 Li3(PO4) + 3 H2
KClO3 + AgOH = AgCl + KOH + O2 =>
2 KClO3 + 2 AgOH = 2 AgCl + 2 KOH + 3 O2
Zn(NO3)2 + H2O2 = H2Zn + O2 + NO3 =>
Zn(NO3)2 + H2O2 = H2Zn + O2 + 2 NO3
NaHCO3 + HCH3COO = NaCH2COO + H2O + CO2 =>
8 NaHCO3 + 7 HCH3COO = 8 NaCH2COO + 10 H2O + 6 CO2
Li + H3(PO4) = Li3(PO4) + H2 =>
6 Li + 2 H3(PO4) = 2 Li3(PO4) + 3 H2
CH3COOH + CH3Cl = CH3COOCH3*HCl =>
CH3COOH + CH3Cl = CH3COOCH3*HCl
Mg + CO2 = MgO + C =>
2 Mg + CO2 = 2 MgO + C
KIO3 + Al + HCl = I2 + KCl + H2O + AlCl3 =>
6 KIO3 + 10 Al + 36 HCl = 3 I2 + 6 KCl + 18 H2O + 10 AlCl3
Li + H3(PO4) = Li(PO4) + H2 =>
2 Li + 2 H3(PO4) = 2 Li(PO4) + 3 H2
Zn + C4SO4 = C1 + ZnSO4 =>
Zn + C4SO4 = 4 C1 + ZnSO4
NaMnO4 + H2SO4 + HOCH2COONa = H2O + Na2SO4 + MnSO4 + HOOCCH2COOH =>
4 NaMnO4 + 21 H2SO4 + 30 HOCH2COONa = 26 H2O + 17 Na2SO4 + 4 MnSO4 + 20 HOOCCH2COOH
H2SO4 + CH2COO = C2H4 + SO4 + O2 =>
H2SO4 + CH2COO = C2H4 + SO4 + O2
ZnSO4 + Cr(PO4)2 = CrSO4 + Zn(PO4)2 =>
ZnSO4 + Cr(PO4)2 = CrSO4 + Zn(PO4)2
NaMnO4 + H2SO4 + HOCH2COONa = H2O + Na2SO4 + MnSO4 + HOOCCH2COOH =>
4 NaMnO4 + 21 H2SO4 + 30 HOCH2COONa = 26 H2O + 17 Na2SO4 + 4 MnSO4 + 20 HOOCCH2COOH
ZnCl2 + (NH4)3PO4 = NH4Cl + Zn3(PO4)2 =>
3 ZnCl2 + 2(NH4)3PO4 = 6 NH4Cl + Zn3(PO4)2
NH4Cl + Ca(OH)2 = CaCl2 + NH3 + H2O =>
2 NH4Cl + Ca(OH)2 = CaCl2 + 2 NH3 + 2 H2O
Mg(NO3)2 = MgO + NO2 + O2 =>
2 Mg(NO3)2 = 2 MgO + 4 NO2 + O2
NaMnO4 + H2SO4 + HOCH2COONa = H2O + Na2SO4 + MnSO4 + HOOCCH2COOH =>
4 NaMnO4 + 21 H2SO4 + 30 HOCH2COONa = 26 H2O + 17 Na2SO4 + 4 MnSO4 + 20 HOOCCH2COOH
Al + CuCl2 = AlCl3 + Cu =>
2 Al + 3 CuCl2 = 2 AlCl3 + 3 Cu
PbO + Ca(OH)2 + H2O = Ca(Pb(OH)4) =>
PbO + Ca(OH)2 + H2O = Ca(Pb(OH)4)
C16H128N13 + O2 = CO2 + H2O + N2 =>
2 C16H128N13 + 96 O2 = 32 CO2 + 128 H2O + 13 N2
Pb(C2H3O2)4(aq) + NH4OH(aq) = Pb(OH)4(aq) + NH4C2H3O2(s) =>
Pb(C2H3O2)4(aq) + 4 NH4OH(aq) = Pb(OH)4(aq) + 4 NH4C2H3O2(s)
Pu + H2O2 = Pu2O7 + H2O =>
2 Pu + 7 H2O2 = Pu2O7 + 7 H2O
Cr3{+} + MnO2 + OH{-} = CrO4{-}2 + Mn2{+} + H2O =>
7 Cr3{+} + 40 MnO2 + 8 OH{-} = 21 CrO4{-}2 + 20 Mn2{+} + 4 H2O
Na(OH)2 + H2CO3 = NaCO3 + H2O =>
Na(OH)2 + H2CO3 = NaCO3 + 2 H2O
Cu + HNO3 = Cu{2+} + HO{-} + NO2 =>
Cu + 2 HNO3 = Cu{2+} + 2 HO{-} + 2 NO2
Na(OH)2 + H2CO3 = NaCO3 + H2O =>
Na(OH)2 + H2CO3 = NaCO3 + 2 H2O
Be(SO4) + NaOH = Be(OH)2 + Na2(SO4) =>
Be(SO4) + 2 NaOH = Be(OH)2 + Na2(SO4)
Fe(NO3)3 + Ba(NO3)2 = Ba(NO3)3 + Fe(NO3)2 =>
Fe(NO3)3 + Ba(NO3)2 = Ba(NO3)3 + Fe(NO3)2
Al(ClO2)3 = AlCl3 + O2 =>
Al(ClO2)3 = AlCl3 + 3 O2
SO3 + HF = H2O + SO2 + F2 =>
SO3 + 2 HF = H2O + SO2 + F2
Na(OH)2 + H2CO3 = NaCO3 + H2O =>
Na(OH)2 + H2CO3 = NaCO3 + 2 H2O
Cu + HNO3 + H{+} = Cu{2+} + NO + H2O =>
3 Cu + 2 HNO3 + 6 H{+} = 3 Cu{2+} + 2 NO + 4 H2O
K2CrO4 + Pb(NO3)2 = KNO3 + PbCrO4 =>
K2CrO4 + Pb(NO3)2 = 2 KNO3 + PbCrO4
Na(OH)2 + H2CO3 = NaCO3 + H2O =>
Na(OH)2 + H2CO3 = NaCO3 + 2 H2O
Al(ClO2)3 = AlCl3 + O2 =>
Al(ClO2)3 = AlCl3 + 3 O2
CO(NH2)2 = C3H6N6 + NH3 + CO2 =>
6 CO(NH2)2 = C3H6N6 + 6 NH3 + 3 CO2
Fe{2+} + H3O{+} + NO3{-} = NO + Fe{3+} + H2O =>
3 Fe{2+} + 4 H3O{+} + NO3{-} = NO + 3 Fe{3+} + 6 H2O
KClO4 + Na2SO3 + H2SO4 = Cl2 + K2SO4 + NaSO4 + H2O =>
4 KClO4 + 7 Na2SO3 + 9 H2SO4 = 2 Cl2 + 2 K2SO4 + 14 NaSO4 + 9 H2O
FeCl2 + FeCl3 + NaCN = Fe4[Fe(CN)6]3 + NaCl =>
3 FeCl2 + 4 FeCl3 + 18 NaCN = Fe4[Fe(CN)6]3 + 18 NaCl
KClO4 + Na2SO3 + H2SO4 = Cl2 + K2SO4 + NaSO4 + H2O =>
4 KClO4 + 7 Na2SO3 + 9 H2SO4 = 2 Cl2 + 2 K2SO4 + 14 NaSO4 + 9 H2O
calciumchloride + sodiumbicarbonate + water = sodiumchloride + calciumhydroxide + carbonicacid =>
CaCl2 + 2 NaHCO3 + 2 H2O = 2 NaCl + Ca(OH)2 + 2 H2CO3
BaCO3 + CH3COOH = Ba(CH3COO) + CO2 + H2O =>
8 BaCO3 + 9 CH3COOH = 8 Ba(CH3COO) + 10 CO2 + 6 H2O
BaCO3 + CH3COOH = Ba(CH3COO) + CO2 + H2O =>
8 BaCO3 + 9 CH3COOH = 8 Ba(CH3COO) + 10 CO2 + 6 H2O
BaCO3 + CH3COOH = Ba(CH3COO) + CO2 + H2O =>
8 BaCO3 + 9 CH3COOH = 8 Ba(CH3COO) + 10 CO2 + 6 H2O
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Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 11/24/23
Equations balanced on 12/24/22
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