Equations balanced on the previous day | Equations balanced on the next day |
2 Sb + 10 HNO3 = H2Sb2O6 + 10 NO2 + 4 H2O
SiO2 + Ca = Si + CaO2 =>
SiO2 + Ca = Si + CaO2
K2SO4 + Al2(SO4)3 + H2O = KAl3(SO4)2(OH)6 + H2SO4 =>
K2SO4 + 3 Al2(SO4)3 + 12 H2O = 2 KAl3(SO4)2(OH)6 + 6 H2SO4
Na2SiO3 + H2 = Na + H2SiO3 =>
Na2SiO3 + H2 = 2 Na + H2SiO3
(NH2)2CO + Ca(OH)2 = NH3 + H2O + Ca(CNO)2 =>
2(NH2)2CO + Ca(OH)2 = 2 NH3 + 2 H2O + Ca(CNO)2
NaCl(aq) + Mg(NO3)2(aq) = NaNO3(aq) + MgCl2(aq) =>
2 NaCl(aq) + Mg(NO3)2(aq) = 2 NaNO3(aq) + MgCl2(aq)
Na3PO4 + NaCl + CuO + H2O = CuPO4 + ClO + NaH2O =>
Na3PO4 + NaCl + CuO + 4 H2O = CuPO4 + ClO + 4 NaH2O
Mg(NO3)2(aq) + NaCl(aq) = MgCl2 + NaNO3 =>
Mg(NO3)2(aq) + 2 NaCl(aq) = MgCl2 + 2 NaNO3
K2SO4 + Al2(SO4)3 + H2O = KAl3(SO4)2(OH)6 + H2SO4 =>
K2SO4 + 3 Al2(SO4)3 + 12 H2O = 2 KAl3(SO4)2(OH)6 + 6 H2SO4
(NH2)2CO + Ca(OH)2 = NH3 + H2O + Ca(CNO)2 =>
2(NH2)2CO + Ca(OH)2 = 2 NH3 + 2 H2O + Ca(CNO)2
(NH2)2CO + Ca(OH)2 = NH3 + H2O + Ca(CNO)2 =>
2(NH2)2CO + Ca(OH)2 = 2 NH3 + 2 H2O + Ca(CNO)2
Sb + HNO3 = H2Sb2O6 + NO2 + H2O =>
2 Sb + 10 HNO3 = H2Sb2O6 + 10 NO2 + 4 H2O
HBr(aq) + NiS(s) = H2S(g) + NiBr2(s) =>
2 HBr(aq) + NiS(s) = H2S(g) + NiBr2(s)
Pb(NO3)2 + KCrO4 = PbCrO4 + K(NO3)2 =>
Pb(NO3)2 + KCrO4 = PbCrO4 + K(NO3)2
NaCl(aq) + Mg(NO3)2(aq) = NaNO3(aq) + MgCl2 =>
2 NaCl(aq) + Mg(NO3)2(aq) = 2 NaNO3(aq) + MgCl2
M + H2SO4 = M2(SO4)3 + SO + H2O =>
4 M + 9 H2SO4 = 2 M2(SO4)3 + 3 SO + 9 H2O
Na3PO4 + NaCl + CuO + H2O = CuPO4 + ClO + NaH2O =>
Na3PO4 + NaCl + CuO + 4 H2O = CuPO4 + ClO + 4 NaH2O
SiO2 + Ca = Si + CaO2 =>
SiO2 + Ca = Si + CaO2
NaCl(aq) + Mg(NO3)2(aq) = NaNO3(aq) + MgCl2(s) =>
2 NaCl(aq) + Mg(NO3)2(aq) = 2 NaNO3(aq) + MgCl2(s)
Na3PO4 + NaCl + CuO + H2O = CuPO4 + ClO + NaH2O =>
Na3PO4 + NaCl + CuO + 4 H2O = CuPO4 + ClO + 4 NaH2O
M + H2SO4 = M2(SO4)3 + SO + H2O =>
4 M + 9 H2SO4 = 2 M2(SO4)3 + 3 SO + 9 H2O
Sb + HNO3 = H2Sb2O6 + NO2 + H2O =>
2 Sb + 10 HNO3 = H2Sb2O6 + 10 NO2 + 4 H2O
K2SO4 + Al2(SO4)3 + H2O = KAl3(SO4)2(OH)6 + H2SO4 =>
K2SO4 + 3 Al2(SO4)3 + 12 H2O = 2 KAl3(SO4)2(OH)6 + 6 H2SO4
NO + H2 = N2 + H2O =>
2 NO + 2 H2 = N2 + 2 H2O
FeCl2 + K1Mn1O4 + HCl = FeCl3 + KCl + MnCl2 + H2O =>
5 FeCl2 + K1Mn1O4 + 8 HCl = 5 FeCl3 + KCl + MnCl2 + 4 H2O
MgCl2(s) + H2SO4(l) = MgSO4(aq) + HCl(g) =>
MgCl2(s) + H2SO4(l) = MgSO4(aq) + 2 HCl(g)
(NH2)2CO + Ca(OH)2 = NH3 + H2O + Ca(CNO)2 =>
2(NH2)2CO + Ca(OH)2 = 2 NH3 + 2 H2O + Ca(CNO)2
PbCl + NaI = NaCl + PbI =>
PbCl + NaI = NaCl + PbI
Ca(OH)2 + NH4Cl = Ca(Cl)2 + H2O + NH3 =>
Ca(OH)2 + 2 NH4Cl = Ca(Cl)2 + 2 H2O + 2 NH3
C2H4(OH)2 + O2 = H2O + CO2 =>
2 C2H4(OH)2 + 5 O2 = 6 H2O + 4 CO2
Cr2O3 + V2O5 = CrVO4 =>
Cr2O3 + V2O5 = 2 CrVO4
Br2 + PBr3 = PBr5 =>
Br2 + PBr3 = PBr5
C10H12O4S + O = CO2 + SO2 + H2O =>
C10H12O4S + 24 O = 10 CO2 + SO2 + 6 H2O
HCl + CO3 = H2O + CO2 + Cl =>
2 HCl + CO3 = H2O + CO2 + 2 Cl
Fe2 + SO3 = FeSO3 =>
Fe2 + 2 SO3 = 2 FeSO3
Mo2 + Os7 + O23 = Mo2Os9O3 =>
161 Mo2 + 207 Os7 + 21 O23 = 161 Mo2Os9O3
HNO2 + KMnO4 + H2SO4 = MnSO4 + HNO3 + K2SO4 + H2O =>
5 HNO2 + 2 KMnO4 + 3 H2SO4 = 2 MnSO4 + 5 HNO3 + K2SO4 + 3 H2O
NH4SO4 + CaOH = CaSO4 + NH3 + H2O =>
NH4SO4 + CaOH = CaSO4 + NH3 + H2O
Cr2O3 + V2O5 = CrVO4 =>
Cr2O3 + V2O5 = 2 CrVO4
N2 + O2 + H2O = HNO3 =>
2 N2 + 5 O2 + 2 H2O = 4 HNO3
Cr2O3 + V2O5 = CrVO4 =>
Cr2O3 + V2O5 = 2 CrVO4
P4O10 + K2O = K3PO4 =>
P4O10 + 6 K2O = 4 K3PO4
SO2 + K2Cr2O7{2-} + H2SO4 = K2SO4{2-} + Cr2(SO4)3 + H2O =>
3 SO2 + K2Cr2O7{2-} + H2SO4 = K2SO4{2-} + Cr2(SO4)3 + H2O
NaO + H2O = Na(OH) + O2 =>
4 NaO + 2 H2O = 4 Na(OH) + O2
Mn(s) + HBr(aq) = MnBr(aq) + H(g) =>
Mn(s) + HBr(aq) = MnBr(aq) + H(g)
PbS + Na2O = PbO + Na2S =>
PbS + Na2O = PbO + Na2S
Ba2 + O2 = BaO2 =>
Ba2 + 2 O2 = 2 BaO2
H2SO4 + FeCl2 = Fe2(SO4)3 + FeCl3 + H2O + SO2 =>
6 H2SO4 + 6 FeCl2 = Fe2(SO4)3 + 4 FeCl3 + 6 H2O + 3 SO2
Cr2O3 + V2O5 = CrVO4 =>
Cr2O3 + V2O5 = 2 CrVO4
Ga + Ge2(CrO4)4 = Ge + Ga2(CrO4)3 =>
8 Ga + 3 Ge2(CrO4)4 = 6 Ge + 4 Ga2(CrO4)3
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 11/20/23
Equations balanced on 12/20/22
Please let us know how we can improve this web app.