Equations balanced on the previous day | Equations balanced on the next day |
Sn + 2 Cl2(g) = SnCl4(l)
H2S + SO2 = S + H2O =>
2 H2S + SO2 = 3 S + 2 H2O
P2O5 + H2O = H3PO4 =>
P2O5 + 3 H2O = 2 H3PO4
Na(HCO3)(aq) + HCl = NaCl + H2O + CO2 =>
Na(HCO3)(aq) + HCl = NaCl + H2O + CO2
K + P2 = K3P =>
6 K + P2 = 2 K3P
C16H18CIN3S{+} + C6H8O6 = C16H19CIN3S{+} + C6H6O6 =>
2 C16H18CIN3S{+} + C6H8O6 = 2 C16H19CIN3S{+} + C6H6O6
Zn + PbN2 = ZnN + Pb =>
2 Zn + PbN2 = 2 ZnN + Pb
Be + HCl = BeCl2 + H2 =>
Be + 2 HCl = BeCl2 + H2
Al + HCl = Al3{+} + H2 + Cl{-} =>
6 Al + 2 HCl = 2 Al3{+} + H2 + 2 Cl{-}
C6H12O6 = C2H6O + CO2 =>
C6H12O6 = 2 C2H6O + 2 CO2
Ag + KCl = K + AgCl2 =>
Ag + 2 KCl = 2 K + AgCl2
Al(OH)3 + H = H2O + Al3 =>
3 Al(OH)3 + 9 H = 9 H2O + Al3
Zn + AgNo3 = Ag + ZnNo =>
3 Zn + AgNo3 = Ag + 3 ZnNo
C12H2O11 + H2O = C2H2OH + CO2 =>
9 C12H2O11 + 33 H2O = 28 C2H2OH + 52 CO2
Li + NaCl = LiNaCl =>
Li + NaCl = LiNaCl
Na2O2 + H2SO4 = Na2SO4 + H2O2 =>
Na2O2 + H2SO4 = Na2SO4 + H2O2
Al + H2SO4 = Al2(SO4)3 + H2 =>
2 Al + 3 H2SO4 = Al2(SO4)3 + 3 H2
K2ZnO2 + HCl = KCl + ZnO + H2O =>
K2ZnO2 + 2 HCl = 2 KCl + ZnO + H2O
C5H9O + O2 = CO2 + H2H =>
2 C5H9O + 9 O2 = 10 CO2 + 6 H2H
ClCH2COOH = H{+} + ClCH2COO{-} =>
ClCH2COOH = H{+} + ClCH2COO{-}
Cu(No3)2 + NaI = CuI + I2 + NaNo3 =>
2 Cu(No3)2 + 4 NaI = 2 CuI + I2 + 4 NaNo3
HFO2 + Ca(OH)2 = Ca(FO2)2 + H2O =>
2 HFO2 + Ca(OH)2 = Ca(FO2)2 + 2 H2O
Cr(NO3) + Na2(SO4) = Na2(NO3) + CrSO4 =>
Cr(NO3) + Na2(SO4) = Na2(NO3) + CrSO4
UO3 + BrF3 = UF4 + Br2 + O2 =>
6 UO3 + 8 BrF3 = 6 UF4 + 4 Br2 + 9 O2
K2Cr2O7 + H2SO4 + CH3COOH = K2SO4 + Cr2(SO4)3 + H2O + CO2 =>
4 K2Cr2O7 + 16 H2SO4 + 3 CH3COOH = 4 K2SO4 + 4 Cr2(SO4)3 + 22 H2O + 6 CO2
Ag2(CrO)4 + NaCl = Na2(CrO)4 + AgCl =>
Ag2(CrO)4 + 2 NaCl = Na2(CrO)4 + 2 AgCl
Al(NO3)3*9H2O + (HOOCCH2)2C(OH)COOH = Al2O3 + H2O + N2 + CO2 =>
6 Al(NO3)3*9H2O + 5(HOOCCH2)2C(OH)COOH = 3 Al2O3 + 74 H2O + 9 N2 + 30 CO2
Ni(NO3)2 + C2H5O2N = NiO + N2 + CO2 + H2O =>
9 Ni(NO3)2 + 10 C2H5O2N = 9 NiO + 14 N2 + 20 CO2 + 25 H2O
CaOHHP = CaPH2O =>
CaOHHP = CaPH2O
Cu(NO) + NaOH = (CuOH) + NaNO =>
Cu(NO) + NaOH = (CuOH) + NaNO
K2Cr2O7 + H2SO4 + CH3COOH = K2SO4 + Cr2(SO4)3 + H2O + CO2 =>
4 K2Cr2O7 + 16 H2SO4 + 3 CH3COOH = 4 K2SO4 + 4 Cr2(SO4)3 + 22 H2O + 6 CO2
Si + HNO3 = SiO2 + H2O + NO2 =>
Si + 4 HNO3 = SiO2 + 2 H2O + 4 NO2
C28H7O2 + O3 = CO2 + H2O =>
6 C28H7O2 + 115 O3 = 168 CO2 + 21 H2O
Na2CO3 + H2O + CrCl3 = NaCl + NaHCO3 + Cr(OH)3 =>
3 Na2CO3 + 3 H2O + CrCl3 = 3 NaCl + 3 NaHCO3 + Cr(OH)3
Cu(NO3)2(aq) + Na2Cr2O7(aq) = CuCr2O7(s) + NaNO3(aq) =>
Cu(NO3)2(aq) + Na2Cr2O7(aq) = CuCr2O7(s) + 2 NaNO3(aq)
NH4NO3 + Ca(OH)2 = CaNO3 + H2O + NH3 =>
7 NH4NO3 + 8 Ca(OH)2 = 8 CaNO3 + 13 H2O + 6 NH3
K2CrO4 + H2SO4 + C6H12O6 = CO2 + Cr2(SO4)3 + K2SO4 + H2O =>
8 K2CrO4 + 20 H2SO4 + C6H12O6 = 6 CO2 + 4 Cr2(SO4)3 + 8 K2SO4 + 26 H2O
(NH4)2Fe(SO4)2 + BaCl2 = (NH4)2Ba(SO4)2 + FeCl2 =>
(NH4)2Fe(SO4)2 + BaCl2 = (NH4)2Ba(SO4)2 + FeCl2
ZnCl2NaOH = ZnOHNaCl2 =>
ZnCl2NaOH = ZnOHNaCl2
NiS + HNO3 = Ni(NO3) + NO + S + H2O =>
3 NiS + 4 HNO3 = 3 Ni(NO3) + NO + 3 S + 2 H2O
K2Cr2O7 + H2SO4 + CH3COOH = K2SO4 + Cr2(SO4)3 + H2O + CO2 =>
4 K2Cr2O7 + 16 H2SO4 + 3 CH3COOH = 4 K2SO4 + 4 Cr2(SO4)3 + 22 H2O + 6 CO2
K2Cr2O7 + H2SO4 + CH3COOH = K2SO4 + Cr2(SO4)3 + H2O + CO2 =>
4 K2Cr2O7 + 16 H2SO4 + 3 CH3COOH = 4 K2SO4 + 4 Cr2(SO4)3 + 22 H2O + 6 CO2
NH + CuO = Cu + H2O + NO2 =>
2 NH + 5 CuO = 5 Cu + H2O + 2 NO2
K2Cr2O7 + H2SO4 + CH3COOH = K2SO4 + Cr2(SO4)3 + H2O + CO2 =>
4 K2Cr2O7 + 16 H2SO4 + 3 CH3COOH = 4 K2SO4 + 4 Cr2(SO4)3 + 22 H2O + 6 CO2
La2O3 + H2O = LaO3H3 =>
La2O3 + 3 H2O = 2 LaO3H3
Ba(OH)2 + NH4SCN = Ba(SCN)2 + H2O + NH3 =>
Ba(OH)2 + 2 NH4SCN = Ba(SCN)2 + 2 H2O + 2 NH3
HBr + Zn = Br2Zn + H =>
2 HBr + Zn = Br2Zn + 2 H
Ca(PO4) + Pb(SO4) = Ca(SO4) + Pb(PO4) =>
Ca(PO4) + Pb(SO4) = Ca(SO4) + Pb(PO4)
NH4Cl + H2O = NH3*H2O + HCl =>
NH4Cl + H2O = NH3*H2O + HCl
Be + H2O = Be(OH)2 + H2 =>
Be + 2 H2O = Be(OH)2 + H2
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 11/18/23
Equations balanced on 12/18/22
Please let us know how we can improve this web app.