Equations balanced on the previous day | Equations balanced on the next day |
Na2S + PbCrO4 = Na2CrO4 + PbS
Al + O2 = Al2O3 =>
4 Al + 3 O2 = 2 Al2O3
Na2[Zn(OH)4] + CuSO4 = Cu[Zn(OH)4] + Na2SO4 =>
Na2[Zn(OH)4] + CuSO4 = Cu[Zn(OH)4] + Na2SO4
C7H8 + O2 = CO2 + H2O =>
C7H8 + 9 O2 = 7 CO2 + 4 H2O
Br{-} + BrO3 + H{+} = Br2 + H2O =>
12 Br{-} + 2 BrO3 + 12 H{+} = 7 Br2 + 6 H2O
AgNO3 + NaCO3 = AgCO3 + NO3 + Na =>
AgNO3 + NaCO3 = AgCO3 + NO3 + Na
H2SO4 + KOH = K2SO4 + H2O =>
H2SO4 + 2 KOH = K2SO4 + 2 H2O
I2 + KOH = KIO2 + KI + H2O =>
2 I2 + 4 KOH = KIO2 + 3 KI + 2 H2O
PbNO3 + NaOH = Pb(OH) + NaNO3 =>
PbNO3 + NaOH = Pb(OH) + NaNO3
FeAsS + Fe{3+} + H2O = Fe{2+} + HAsO4{2-} + SO4{2-} + H{+} =>
FeAsS + 13 Fe{3+} + 8 H2O = 14 Fe{2+} + HAsO4{2-} + SO4{2-} + 15 H{+}
KMnO4 + FeCl + HCl = MnCl2 + FeCl3 + KCl + H2O =>
2 KMnO4 + 5 FeCl + 16 HCl = 2 MnCl2 + 5 FeCl3 + 2 KCl + 8 H2O
FeCl{3} + NaOH = Fe(OH){3} + NaCl =>
FeCl{3} + NaOH = Fe(OH){3} + NaCl
S + Cl2 = SCl6 =>
S + 3 Cl2 = SCl6
Cr2(SO4)3 + Na2CO3 + H2O = Cr(OH)3 + Na2SO4 + CO2 =>
Cr2(SO4)3 + 3 Na2CO3 + 3 H2O = 2 Cr(OH)3 + 3 Na2SO4 + 3 CO2
K3[Fe(CN)6] + Ca(NO3)2 = KNO3 + Ca3[Fe(CN)6]2 =>
2 K3[Fe(CN)6] + 3 Ca(NO3)2 = 6 KNO3 + Ca3[Fe(CN)6]2
CuO + BeO = CuBeO2 =>
CuO + BeO = CuBeO2
BaCrO4 + CH3COOH = CrCOOH + H2O + BaOH + CO2 =>
BaCrO4 + CH3COOH = CrCOOH + H2O + BaOH + CO2
Fe + K4[Fe(CN)6] = Fe4[Fe(CN)6]3 + K =>
4 Fe + 3 K4[Fe(CN)6] = Fe4[Fe(CN)6]3 + 12 K
Na2HAsO3 + NaBrO3 + HCl = NaCl + NaBr + H3AsO4 =>
3 Na2HAsO3 + NaBrO3 + 6 HCl = 6 NaCl + NaBr + 3 H3AsO4
NaClO(aq) + Cl2(g) = ClO2(g) + NaCl(aq) =>
4 NaClO(aq) + Cl2(g) = 2 ClO2(g) + 4 NaCl(aq)
NH3 + O2 = NO + H2O =>
4 NH3 + 5 O2 = 4 NO + 6 H2O
Zn(NO3) + NaOH = Zn(OH) + Na(NO3) =>
Zn(NO3) + NaOH = Zn(OH) + Na(NO3)
Fe + K4[Fe(CN)6] = Fe4[Fe(CN)6]3 + K =>
4 Fe + 3 K4[Fe(CN)6] = Fe4[Fe(CN)6]3 + 12 K
K3[Fe(CN6)] + NaOH = Na3[Fe(CN6)] + KOH =>
K3[Fe(CN6)] + 3 NaOH = Na3[Fe(CN6)] + 3 KOH
Pb(NO3)2 + AgCl = PbCl2 + AgNO3 =>
Pb(NO3)2 + 2 AgCl = PbCl2 + 2 AgNO3
AgNO3 + NaCO3 = AgCO3 + NO3 + Na =>
AgNO3 + NaCO3 = AgCO3 + NO3 + Na
Zn + H2SO4 = ZnSO4 + H2S + H2O =>
4 Zn + 5 H2SO4 = 4 ZnSO4 + H2S + 4 H2O
AgNO3 + NaCO3 = AgCO3 + NO3 + Na =>
AgNO3 + NaCO3 = AgCO3 + NO3 + Na
Ba(HCO3)2 + HNO3 = Ba(NO3)2 + H2CO3 =>
Ba(HCO3)2 + 2 HNO3 = Ba(NO3)2 + 2 H2CO3
AgNO3 + NaCO3 = AgCO3 + NO3 + Na =>
AgNO3 + NaCO3 = AgCO3 + NO3 + Na
HNO3 = NO2 + H2O + O2 =>
4 HNO3 = 4 NO2 + 2 H2O + O2
LiOH + LiHSO4 = Li2SO4 + H2O =>
LiOH + LiHSO4 = Li2SO4 + H2O
InCl2 + H2O = InOHCl + HCl =>
InCl2 + H2O = InOHCl + HCl
Sr2SiO4 = SrO + SiO2 =>
Sr2SiO4 = 2 SrO + SiO2
AgNO3 + NaCO3 = AgCO3 + NO3 + Na =>
AgNO3 + NaCO3 = AgCO3 + NO3 + Na
C4(s) + O2(g) = CO2(g) =>
C4(s) + 4 O2(g) = 4 CO2(g)
CH3COOH + C6H6O = CH3COO + C6H7 =>
8 CH3COOH + 6 C6H6O = 11 CH3COO + 5 C6H7
NaBrO3 + XeF4 + NaOH = NaBrO4 + Xe + NaF + H2O =>
2 NaBrO3 + XeF4 + 4 NaOH = 2 NaBrO4 + Xe + 4 NaF + 2 H2O
NaCO3 + CH3COOH = CO2 + C2H3NaO2 + H2O =>
8 NaCO3 + 9 CH3COOH = 10 CO2 + 8 C2H3NaO2 + 6 H2O
AgNO3 + NaCO3 = AgCO3 + NO3 + Na =>
AgNO3 + NaCO3 = AgCO3 + NO3 + Na
Ba + H2O = BaO + H2 =>
Ba + H2O = BaO + H2
AgNO3 + NaCO3 = AgCO3 + NO3 + Na =>
AgNO3 + NaCO3 = AgCO3 + NO3 + Na
Na2S + PbCrO4 = Na2CrO4 + PbS =>
Na2S + PbCrO4 = Na2CrO4 + PbS
Li + F = LiF =>
Li + F = LiF
HCl + KCr2O7 = CrCl3 + KCl + Cl2 + H2O =>
28 HCl + 2 KCr2O7 = 4 CrCl3 + 2 KCl + 7 Cl2 + 14 H2O
NH4I + MgSO4 = (NH4)2SO4 + MgI2 =>
2 NH4I + MgSO4 = (NH4)2SO4 + MgI2
AlBr3 + AgNO3 = Al(NO3)3 + AgBr =>
AlBr3 + 3 AgNO3 = Al(NO3)3 + 3 AgBr
MnO2 + AlCl3 + H2SO4 = MnSO4 + Cl2 + Al2(SO4)3 + H2O =>
3 MnO2 + 2 AlCl3 + 6 H2SO4 = 3 MnSO4 + 3 Cl2 + Al2(SO4)3 + 6 H2O
NaHCO3 + HC2H3O = NaC2H3O2 + H2O + CO2 =>
5 NaHCO3 + 4 HC2H3O = 5 NaC2H3O2 + 3 H2O + 3 CO2
K3[Fe(SCN)6] + Na2Cr2O7 + H2SO4 = Fe(NO3)3 + Cr2(SO4)3 + CO2 + H2O + NaSO4 + KNO3 =>
K3[Fe(SCN)6] + 24 Na2Cr2O7 + 114 H2SO4 = Fe(NO3)3 + 24 Cr2(SO4)3 + 6 CO2 + 114 H2O + 48 NaSO4 + 3 KNO3
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 11/17/23
Equations balanced on 12/17/22
Please let us know how we can improve this web app.