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Chemical Equations Balanced on 12/25/15

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Au + NaCN + H2O + O2 = Na[Au(CN)2] + NaOH =>
4 Au + 8 NaCN + 2 H2O + O2 = 4 Na[Au(CN)2] + 4 NaOH

NaOH + H2SO4 = Na2SO4 + H2O =>
2 NaOH + H2SO4 = Na2SO4 + 2 H2O

MnO2 + Al = Al2O3 + Mn =>
3 MnO2 + 4 Al = 2 Al2O3 + 3 Mn

Cu(OH)2 + Na = NaOH + Cu =>
Cu(OH)2 + 2 Na = 2 NaOH + Cu

Mg(oh)2 + H2SO4 = MgSO4 + H20 =>
5 Mg(oh)2 + 10 H2SO4 = 10 MgSO4 + H20

S + NaOH = Na2S + Na2S2O3 + H2O =>
4 S + 6 NaOH = 2 Na2S + Na2S2O3 + 3 H2O

Al + Cl2 = AlCl3 =>
2 Al + 3 Cl2 = 2 AlCl3

Pb(NO3)2 + Na2SO4 = NaNO3 + PbSO4 =>
Pb(NO3)2 + Na2SO4 = 2 NaNO3 + PbSO4

S + NaOH = Na2S + Na2S2O3 + H2O =>
4 S + 6 NaOH = 2 Na2S + Na2S2O3 + 3 H2O

MgO + HCl = MgCl2 + H2O =>
MgO + 2 HCl = MgCl2 + H2O

KOH + Cl2 = KClO + KCl + H2O =>
2 KOH + Cl2 = KClO + KCl + H2O

S + NaOH = Na2S + Na2S2O3 + H2O =>
4 S + 6 NaOH = 2 Na2S + Na2S2O3 + 3 H2O

NaOH + H2SO4 = Na2SO4 + H2O =>
2 NaOH + H2SO4 = Na2SO4 + 2 H2O

NH3 + O2 = N2 + H2O =>
4 NH3 + 3 O2 = 2 N2 + 6 H2O

C2H6O + U2Cr2O7 + H2SO4 = C2H4O + Cr2(SO4)3 + H2O + U2SO4 =>
3 C2H6O + U2Cr2O7 + 4 H2SO4 = 3 C2H4O + Cr2(SO4)3 + 7 H2O + U2SO4

Fe2O3 + HCl = FeCl3 + H2O =>
Fe2O3 + 6 HCl = 2 FeCl3 + 3 H2O

Ni2O3 + HCl = Cl2 + NiCl2 + H2O =>
Ni2O3 + 6 HCl = Cl2 + 2 NiCl2 + 3 H2O

ZnS + HCl = ZnCl2 + H2S =>
ZnS + 2 HCl = ZnCl2 + H2S

C2H6O2 + O2 = CO2 + H20 =>
10 C2H6O2 + 10 O2 = 20 CO2 + 3 H20

AlSo4 + NaOH = AlOH + NaSo4 =>
AlSo4 + NaOH = AlOH + NaSo4

Fe2S3(s) + HCl(g) = FeCl3(s) + H2S(g) =>
Fe2S3(s) + 6 HCl(g) = 2 FeCl3(s) + 3 H2S(g)

CrCl3 + Cl2 + KOH = K2CrO4 + KCl + H2O =>
2 CrCl3 + 3 Cl2 + 16 KOH = 2 K2CrO4 + 12 KCl + 8 H2O

ZnO + NaOH = Na2ZnO2 + H2O =>
ZnO + 2 NaOH = Na2ZnO2 + H2O

Cr{+3} + S2O8{-2} + H2O = CrO4{-2} + SO4{-2} + H{+} =>
2 Cr{+3} + 3 S2O8{-2} + 8 H2O = 2 CrO4{-2} + 6 SO4{-2} + 16 H{+}

Al(OH)3 = Al2O3 + H2O =>
2 Al(OH)3 = Al2O3 + 3 H2O

Fe + HNO3 + H2SO4 = Fe2(SO4)3 + NO + H2O =>
2 Fe + 2 HNO3 + 3 H2SO4 = Fe2(SO4)3 + 2 NO + 4 H2O

SO2 + O2 = SO3 =>
2 SO2 + O2 = 2 SO3

Al + H2O = Al(OH)4 + H2 =>
Al + 4 H2O = Al(OH)4 + 2 H2

Br2 + KOH + KNO2 = KNO3 + H2O + KBr =>
Br2 + 2 KOH + KNO2 = KNO3 + H2O + 2 KBr

H{+} + As2S3 + NO3{-} = HAsO3 + S + NO + H2O =>
10 H{+} + 3 As2S3 + 10 NO3{-} = 6 HAsO3 + 9 S + 10 NO + 2 H2O

AlBr3 + K2SO4 = KBr + Al2(SO4)3 =>
2 AlBr3 + 3 K2SO4 = 6 KBr + Al2(SO4)3

MNO2 + Fe2 = MNO + Fe2O3 =>
3 MNO2 + Fe2 = 3 MNO + Fe2O3

Br2 + KOH + CrCl3 = K2CrO4 + H2O + KBr + KCl =>
3 Br2 + 16 KOH + 2 CrCl3 = 2 K2CrO4 + 8 H2O + 6 KBr + 6 KCl

FeO3 + C = Fe + CO2 =>
2 FeO3 + 3 C = 2 Fe + 3 CO2

Ag + HNO3 = AgNO3 + NO + H2O =>
3 Ag + 4 HNO3 = 3 AgNO3 + NO + 2 H2O

C + O = CO2 =>
C + 2 O = CO2

H2S + SO2 = S + HO2 =>
H2S + 2 SO2 = 3 S + 2 HO2

K4Fe(CN)6 + K2CrO4 + H2SO4 = KHSO4 + Fe2(SO4)3 + Cr2(SO4)3 + HNO3 + CO2 + H2O =>
6 K4Fe(CN)6 + 122 K2CrO4 + 460 H2SO4 = 268 KHSO4 + 3 Fe2(SO4)3 + 61 Cr2(SO4)3 + 36 HNO3 + 36 CO2 + 308 H2O

MnO2 + HCl = MnCl2 + Cl2 + H2O =>
MnO2 + 4 HCl = MnCl2 + Cl2 + 2 H2O

MnO2 + HCl = MnCl2 + Cl2 + H2O =>
MnO2 + 4 HCl = MnCl2 + Cl2 + 2 H2O

K4Fe(CN)6 + K2CrO4 + H2SO4 = K2SO4 + Fe2(SO4)3 + Cr2(SO4)3 + HNO3 + CO2 + H2O =>
6 K4Fe(CN)6 + 122 K2CrO4 + 326 H2SO4 = 134 K2SO4 + 3 Fe2(SO4)3 + 61 Cr2(SO4)3 + 36 HNO3 + 36 CO2 + 308 H2O

KHCO3 + H2SO4 = K2SO4 + CO2 + H2O =>
2 KHCO3 + H2SO4 = K2SO4 + 2 CO2 + 2 H2O

K4Fe(CN)6 + K2CrO4 + HNO3 = KNO3 + Fe(NO3)3 + Cr(NO3)3 + CO2 + H2O =>
3 K4Fe(CN)6 + 61 K2CrO4 + 308 HNO3 = 134 KNO3 + 3 Fe(NO3)3 + 61 Cr(NO3)3 + 18 CO2 + 154 H2O

Cu + H2SO4 = CuSO4 + SO2 + H2O =>
Cu + 2 H2SO4 = CuSO4 + SO2 + 2 H2O

K2Cr2O7 + KY + H2SO4 = Y2 + Cr2(SO4)3 + K2SO4 + H2O =>
K2Cr2O7 + 6 KY + 7 H2SO4 = 3 Y2 + Cr2(SO4)3 + 4 K2SO4 + 7 H2O

C3H8O + KMnO4 + H2SO4 = C3H6O2 + K2SO4 + MnSO4 + H2O =>
5 C3H8O + 4 KMnO4 + 6 H2SO4 = 5 C3H6O2 + 2 K2SO4 + 4 MnSO4 + 11 H2O

Na2 + SnO2 + Bi(OH)3 = Bi + Na2SnO3 + H2O =>
3 Na2 + 3 SnO2 + 2 Bi(OH)3 = 2 Bi + 3 Na2SnO3 + 3 H2O

Na3N + HCl = NH4Cl + NaCl =>
Na3N + 4 HCl = NH4Cl + 3 NaCl

NaOH + H2So4 = Na2So4 + H2O =>
2 NaOH + H2So4 = Na2So4 + 2 H2O

Rb + ZnO = RbO + Zn =>
Rb + ZnO = RbO + Zn

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Balance equation of any chemical reaction online for free
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Equations balanced on 12/18/15
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Equations balanced on 12/25/14
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