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Chemical Equations Balanced on 08/03/09

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Na + H2O = NaOH + H2 =>
2 Na + 2 H2O = 2 NaOH + H2

Al + HCl = AlCl3 + H2 =>
2 Al + 6 HCl = 2 AlCl3 + 3 H2

CH3C8H17 + O2 = CO2 + H2O =>
CH3C8H17 + 14 O2 = 9 CO2 + 10 H2O

Al + FeO = Al2O3 + Fe =>
2 Al + 3 FeO = Al2O3 + 3 Fe

Fe + O2 + H2O = Fe(OH)2 =>
2 Fe + O2 + 2 H2O = 2 Fe(OH)2

K2CrO4 + Na2SO3 + HCl = KCl + Na2SO4 + CrCl3 + H2O =>
2 K2CrO4 + 3 Na2SO3 + 10 HCl = 4 KCl + 3 Na2SO4 + 2 CrCl3 + 5 H2O

KBrO3 = KBr + O2 =>
2 KBrO3 = 2 KBr + 3 O2

C4H10S2 + O2 = CO2 + H2O + SO3 =>
2 C4H10S2 + 19 O2 = 8 CO2 + 10 H2O + 4 SO3

NaC2H3O2 + Fe(NO3)3 = NaNO3 + Fe(C2H3O2)3 =>
3 NaC2H3O2 + Fe(NO3)3 = 3 NaNO3 + Fe(C2H3O2)3

C2H4 + F2 = C2H4F2 =>
C2H4 + F2 = C2H4F2

Na + FeBr3 = NaBr + Fe =>
3 Na + FeBr3 = 3 NaBr + Fe

CuSO4*5H2O = CuSO4 + H2O =>
CuSO4*5H2O = CuSO4 + 5 H2O

HBr + Sn = SnBr + H =>
HBr + Sn = SnBr + H

Fe + Cl2 = FeCl3 =>
2 Fe + 3 Cl2 = 2 FeCl3

HC6H5COO + NaOH = NaC6H5COO + H2O =>
HC6H5COO + NaOH = NaC6H5COO + H2O

VO + Fe2O3 = FeO + V2O5 =>
2 VO + 3 Fe2O3 = 6 FeO + V2O5

Na + H2O = NaOH + H2 =>
2 Na + 2 H2O = 2 NaOH + H2

(NH4)2SO4 + NaOH = NH3 + H2O + Na2SO4 =>
(NH4)2SO4 + 2 NaOH = 2 NH3 + 2 H2O + Na2SO4

NH4NO3 = N2O + H2O =>
NH4NO3 = N2O + 2 H2O

MnO2 + HCl = Cl2 + MnCl2 + H2O =>
MnO2 + 4 HCl = Cl2 + MnCl2 + 2 H2O

HC2H5COO + Ca(OH)2 = CaC2H5COO + H3O2 =>
HC2H5COO + Ca(OH)2 = CaC2H5COO + H3O2

KMnO4 + HCl = KCl + MnCl2 + H2O + Cl2 =>
2 KMnO4 + 16 HCl = 2 KCl + 2 MnCl2 + 8 H2O + 5 Cl2

S + H2SO4 = SO2 + H2O =>
S + 2 H2SO4 = 3 SO2 + 2 H2O

Zn + HNO3 = Zn(NO3)2 + H2O + NO =>
3 Zn + 8 HNO3 = 3 Zn(NO3)2 + 4 H2O + 2 NO

VO + Fe2O3 = FeO + V2O5 =>
2 VO + 3 Fe2O3 = 6 FeO + V2O5

Cu + HNO3 = Cu(NO3)2 + H2O + NO2 =>
Cu + 4 HNO3 = Cu(NO3)2 + 2 H2O + 2 NO2

Na + H2O = NaOH + H2 =>
2 Na + 2 H2O = 2 NaOH + H2

NH4NO3 = N2O + H2O =>
NH4NO3 = N2O + 2 H2O

MnO2 + HCl = Cl2 + MnCl2 + H2O =>
MnO2 + 4 HCl = Cl2 + MnCl2 + 2 H2O

NaC2H3O2 + HCl = NaCl + HC2H3O2 =>
NaC2H3O2 + HCl = NaCl + HC2H3O2

ZnS + HBr = ZnBr + HS =>
ZnS + HBr = ZnBr + HS

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Balance equation of any chemical reaction online for free
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