Equations balanced on the previous day | Equations balanced on the next day |
K2Cr2O7 + 7 H2O + 3 Na2S = 6 NaOH + 2 KOH + 3 S + 2 Cr(OH)3
C3H6O + AgO2 = C2H5COOH + Ag =>
2 C3H6O + AgO2 = 2 C2H5COOH + Ag
Cl + Na2I = NaCl + I =>
2 Cl + Na2I = 2 NaCl + I
NiCl2 + CH3C(NOH)C(NOH)CH3 = NiC4H8N2O2Cl2 =>
NiCl2 + CH3C(NOH)C(NOH)CH3 = NiC4H8N2O2Cl2
(MnO4){-} + H2C2O4 + H{+} = Mn{+}2 + CO2 + H2O =>
(MnO4){-} + 3 H2C2O4 + 2 H{+} = Mn{+}2 + 6 CO2 + 4 H2O
Cl2 + K2S + H2O = K2SO4 + HCl =>
4 Cl2 + K2S + 4 H2O = K2SO4 + 8 HCl
KClO3 = KCl + O2 =>
2 KClO3 = 2 KCl + 3 O2
Ru + NaOH + Cl2 = Na2RuO4 + NaCl + H2O =>
Ru + 8 NaOH + 3 Cl2 = Na2RuO4 + 6 NaCl + 4 H2O
ZnCl2 + KOH = Zn(OH)2 + KCl =>
ZnCl2 + 2 KOH = Zn(OH)2 + 2 KCl
C5H11COH + Cu(OH)2 = C5H11COOH + Cu2O + H2O =>
C5H11COH + 2 Cu(OH)2 = C5H11COOH + Cu2O + 2 H2O
C5H11COH + Cu(OH)2 = C5H11COOH + Cu2O + H2O =>
C5H11COH + 2 Cu(OH)2 = C5H11COOH + Cu2O + 2 H2O
LiCl + Br2 = LiBr + Cl2 =>
2 LiCl + Br2 = 2 LiBr + Cl2
KNO2 + HNO3 = KNO3 + NO2 + H2O =>
KNO2 + 2 HNO3 = KNO3 + 2 NO2 + H2O
Cl + O2 = ClO2 =>
Cl + O2 = ClO2
Fe + Sn(CO3)2 = Sn + Fe(CO3)2 =>
Fe + Sn(CO3)2 = Sn + Fe(CO3)2
K2Cr2O7 + K2S2O4 + H2SO4 = Cr2(SO4)3 + K2SO4 + H2O =>
K2Cr2O7 + K2S2O4 + 3 H2SO4 = Cr2(SO4)3 + 2 K2SO4 + 3 H2O
Li + Cu(OH)2 = Li(OH) + Cu =>
2 Li + Cu(OH)2 = 2 Li(OH) + Cu
(CH3(CH2)OH) + O2 = CO2 + H2O =>
(CH3(CH2)OH) + 3 O2 = 2 CO2 + 3 H2O
C10H16 + Br2 = C10H15Br + HBr =>
C10H16 + Br2 = C10H15Br + HBr
Cu(NO3)2 = CuO + NO2 + O2 =>
2 Cu(NO3)2 = 2 CuO + 4 NO2 + O2
Ba(OH)2 + Mn(C2H3O2)2 = Ba(C2H3O2)2 + Mn(OH)2 =>
Ba(OH)2 + Mn(C2H3O2)2 = Ba(C2H3O2)2 + Mn(OH)2
(Cr(N2HCO)6)4(Cr(CN)6)3 + KMnO4 + H2SO4 = K2Cr2O7 + MnSO4 + CO2 + KNO3 + K2SO4 + H2O =>
10(Cr(N2HCO)6)4(Cr(CN)6)3 + 1032 KMnO4 + 1183 H2SO4 = 35 K2Cr2O7 + 1032 MnSO4 + 420 CO2 + 660 KNO3 + 151 K2SO4 + 1303 H2O
C2H5OH + C2O2OH2 = C4H6O2 + H2O =>
5 C2H5OH + 3 C2O2OH2 = 4 C4H6O2 + 6 H2O
Mg2 + Zn(NO3)2 = Mg(NO3)2 + Zn =>
Mg2 + 2 Zn(NO3)2 = 2 Mg(NO3)2 + 2 Zn
NaOH + BaCI{2} = NaCI + Ba(OH){2} =>
NaOH + BaCI{2} = NaCI + Ba(OH){2}
CrO3 + H2SO4 + Mg = Cr2O3 + MgSO4 + H2O =>
2 CrO3 + 3 H2SO4 + 3 Mg = Cr2O3 + 3 MgSO4 + 3 H2O
C14H18O8 + O2 = CO2 + H2O =>
2 C14H18O8 + 29 O2 = 28 CO2 + 18 H2O
FeCl3 + HCl = FeCl + HCl2 =>
FeCl3 + 2 HCl = FeCl + 2 HCl2
MnI2 + Na3PO4 = Mn3(PO4)2 + NaI =>
3 MnI2 + 2 Na3PO4 = Mn3(PO4)2 + 6 NaI
Cl2 + C2H2 = H2C2Cl4 =>
2 Cl2 + C2H2 = H2C2Cl4
C3H7OH + Al2O3 = C2H5CHO + Al + H2O =>
3 C3H7OH + Al2O3 = 3 C2H5CHO + 2 Al + 3 H2O
BaCl2 + Fe(SO4)3 = Ba(SO4)3 + FeCl2 =>
BaCl2 + Fe(SO4)3 = Ba(SO4)3 + FeCl2
AgNO3(aq) + Cu = CuNO3 + Ag =>
AgNO3(aq) + Cu = CuNO3 + Ag
C6H6O + N2O = CO2 + H2O + N2 =>
C6H6O + 14 N2O = 6 CO2 + 3 H2O + 14 N2
XAgNO3 + K3PO4 = Ag3PO4 + XKNO3 =>
3 XAgNO3 + K3PO4 = Ag3PO4 + 3 XKNO3
AgCl + NaNO3 + NH3 + H2O = AgNO3 + NH4Cl + NaH =>
5 AgCl + 4 NaNO3 + 6 NH3 + 3 H2O = 5 AgNO3 + 5 NH4Cl + 4 NaH
C6H5CO2Na + O2 = Na2CO3 + CO2 + H2O =>
2 C6H5CO2Na + 15 O2 = Na2CO3 + 13 CO2 + 5 H2O
Br2 + KOH = KBrO3 + KBr + H2O =>
3 Br2 + 6 KOH = KBrO3 + 5 KBr + 3 H2O
Fe2(SO4)3 + Zn(NO3)2 = Fe(NO3)3 + ZnSO4 =>
Fe2(SO4)3 + 3 Zn(NO3)2 = 2 Fe(NO3)3 + 3 ZnSO4
Ca(HSO3)2 + HCl = SO2 + CaCl2 + H2O =>
Ca(HSO3)2 + 2 HCl = 2 SO2 + CaCl2 + 2 H2O
AlF3 + Mn3(BO3)2 = AlBO3 + MnF2 =>
2 AlF3 + Mn3(BO3)2 = 2 AlBO3 + 3 MnF2
ZnCl2 + H3PO4 = Zn3(PO4)2 + HCl =>
3 ZnCl2 + 2 H3PO4 = Zn3(PO4)2 + 6 HCl
CuSO4(s) + Na2SiO3(aq) + H2O = Cu(OH)2 + H2SiO3 + Na2SO4 =>
CuSO4(s) + Na2SiO3(aq) + 2 H2O = Cu(OH)2 + H2SiO3 + Na2SO4
Na2CO3 + H2SO4 = Na2SO4 + CO2 + H2O =>
Na2CO3 + H2SO4 = Na2SO4 + CO2 + H2O
Ca + NaOH = Na + CaOH =>
Ca + NaOH = Na + CaOH
SbCl3 + (NH4)2S = SSb + (NH4)2Cl3 =>
SbCl3 + (NH4)2S = SSb + (NH4)2Cl3
KMnO4 + KBr + H2SO4 = H2O + Br2 + K2SO4 + MnSO4 =>
2 KMnO4 + 10 KBr + 8 H2SO4 = 8 H2O + 5 Br2 + 6 K2SO4 + 2 MnSO4
C5H10(OH)2 + O2 = CO + H2O =>
2 C5H10(OH)2 + 9 O2 = 10 CO + 12 H2O
HNO3 + CaCl2 = Ca(NO3) + HCl2 =>
HNO3 + CaCl2 = Ca(NO3) + HCl2
Fe + SCN = FeSCN =>
Fe + SCN = FeSCN
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 03/18/24
Equations balanced on 04/17/23
Please let us know how we can improve this web app.