First, compute the number of each atom in PbBaK2GeZnAl2Na2CaSiMgB2O2OOOO3O3OOOOO2:
Pb: 1, Ba: 1, K: 2, Ge: 1, Zn: 1, Al: 2, Na: 2, Ca: 1, Si: 1, Mg: 1, B: 2, O: 17
Then, lookup atomic weights for each element in periodic table:
Pb: 207.2, Ba: 137.327, K: 39.0983, Ge: 72.64, Zn: 65.38, Al: 26.9815386, Na: 22.98976928, Ca: 40.078, Si: 28.0855, Mg: 24.305, B: 10.811, O: 15.9994
Now, compute the sum of products of number of atoms to the atomic weight:
Molar mass (PbBaK2GeZnAl2Na2CaSiMgB2O2OOOO3O3OOOOO2) = ∑ Counti * Weighti =
Count(Pb) * Weight(Pb) + Count(Ba) * Weight(Ba) + Count(K) * Weight(K) + Count(Ge) * Weight(Ge) + Count(Zn) * Weight(Zn) + Count(Al) * Weight(Al) + Count(Na) * Weight(Na) + Count(Ca) * Weight(Ca) + Count(Si) * Weight(Si) + Count(Mg) * Weight(Mg) + Count(B) * Weight(B) + Count(O) * Weight(O) =
1 * 207.2 + 1 * 137.327 + 2 * 39.0983 + 1 * 72.64 + 1 * 65.38 + 2 * 26.9815386 + 2 * 22.98976928 + 1 * 40.078 + 1 * 28.0855 + 1 * 24.305 + 2 * 10.811 + 17 * 15.9994 =
1046.7665 g/mol
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