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Chemical Equations Balanced on 12/20/24

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Balance the equation of any chemical reaction
FeCl{3+} + NaOH = FeOH{3+} + NaCl =>
FeCl{3+} + NaOH = FeOH{3+} + NaCl

NH3 + CuO3 = Cu + N2 + H2O =>
2 NH3 + CuO3 = Cu + N2 + 3 H2O

NaClO + H2O + S = Cl + Na2SO4 + NaOH =>
6 NaClO + 2 H2O + S = 6 Cl + Na2SO4 + 4 NaOH

Na2Cr2O7 + CH3OH + HNO3 = Cr2(NO3)3 + CH2O2 + NaNO3 + H2O =>
4 Na2Cr2O7 + 9 CH3OH + 20 HNO3 = 4 Cr2(NO3)3 + 9 CH2O2 + 8 NaNO3 + 19 H2O

HBr(aq) + Fe2O3(aq) = FeBr3(aq) + H2O(l) =>
6 HBr(aq) + Fe2O3(aq) = 2 FeBr3(aq) + 3 H2O(l)

Ba(NO3)2 + MgSO4 = BaSO4 + Mg(NO3)2 =>
Ba(NO3)2 + MgSO4 = BaSO4 + Mg(NO3)2

NO2(g) + O2(g) + H2O = HNO3 =>
4 NO2(g) + O2(g) + 2 H2O = 4 HNO3

SnO + CO = Sn + CO2 =>
SnO + CO = Sn + CO2

CH3COOH + CH3CH(OH)CH3 = CH3COOCH(CH3)2 + H2O =>
CH3COOH + CH3CH(OH)CH3 = CH3COOCH(CH3)2 + H2O

C6H6 + O2 = CO2 + H2O =>
2 C6H6 + 15 O2 = 12 CO2 + 6 H2O

Fe(OH)2 + HCl = FeCl3 + H2 + H2O =>
2 Fe(OH)2 + 6 HCl = 2 FeCl3 + H2 + 4 H2O

Li + H2O = LiOH + H =>
Li + H2O = LiOH + H

Cr2(SO4)2 + (NH4)2CO3 = Cr2CO3 + NH4(SO4) =>
Cr2(SO4)2 + (NH4)2CO3 = Cr2CO3 + 2 NH4(SO4)

Cl2O3 + KOH = KClO2 + H2O =>
Cl2O3 + 2 KOH = 2 KClO2 + H2O

NH3 + HNO3 = NH4NO3 =>
NH3 + HNO3 = NH4NO3

Pb(NO3)2 = Pb + NO2 + O2 =>
Pb(NO3)2 = Pb + 2 NO2 + O2

C4H4N2(g) + O2(g) = CO2(g) + H2O(l) + HNO3(g) =>
2 C4H4N2(g) + 15 O2(g) = 8 CO2(g) + 2 H2O(l) + 4 HNO3(g)

Cd(NO3)2 + Li3PO4 = Cd3(PO4)2 + Li(NO3) =>
3 Cd(NO3)2 + 2 Li3PO4 = Cd3(PO4)2 + 6 Li(NO3)

C3H5(NO3)3 = CO + N2 + O2 + H2O =>
4 C3H5(NO3)3 = 12 CO + 6 N2 + 7 O2 + 10 H2O

Ba(OH)2 + HCl = BaCl2 + H2O =>
Ba(OH)2 + 2 HCl = BaCl2 + 2 H2O

H2S + NaHCO3 = H2 + SNaHCO3 =>
H2S + NaHCO3 = H2 + SNaHCO3

KCH3COO + Pb(CH3COO)2 = K(CH3COO)2 + PbCH3COO =>
KCH3COO + Pb(CH3COO)2 = K(CH3COO)2 + PbCH3COO

CH3CH2COOH + Ca = (CH3CH2COO)2Ca + H2 =>
2 CH3CH2COOH + Ca = (CH3CH2COO)2Ca + H2

(C17H33COO)3C3H5 + Ca(OH)2 = (C17H33COO)2Ca + C3H5(OH)3 =>
2(C17H33COO)3C3H5 + 3 Ca(OH)2 = 3(C17H33COO)2Ca + 2 C3H5(OH)3

Ba(OH)2 + HClO3 = O2H3 + BaClO3 =>
Ba(OH)2 + HClO3 = O2H3 + BaClO3

Fe(OH)2 + NaCl = FeCl2 + NaOH =>
Fe(OH)2 + 2 NaCl = FeCl2 + 2 NaOH

CuOZn(OH)2 = Cu(OH)2ZnO =>
CuOZn(OH)2 = Cu(OH)2ZnO

Li(s) + Fe(NO3)3(aq) = Li(NO3)3 + Fe =>
Li(s) + Fe(NO3)3(aq) = Li(NO3)3 + Fe

NH2CH2COOH + HNO3 = HOCH2COOH + N2 + H2O =>
5 NH2CH2COOH + 3 HNO3 = 5 HOCH2COOH + 4 N2 + 4 H2O

CH3CH2CH2COOH + Na2CO3 = CH3CH2CH2CH2Na + CO2 + H2O =>
13 CH3CH2CH2COOH + 5 Na2CO3 = 10 CH3CH2CH2CH2Na + 17 CO2 + 7 H2O

Cr(OH)6 + H2O2 = CrO4 + H2O =>
Cr(OH)6 + H2O2 = CrO4 + 4 H2O

P + I2 + H2O = H3PO4 + HI2 =>
P + 5 I2 + 4 H2O = H3PO4 + 5 HI2

FeCl2 + Cl2 + KOH = K[Fe(OH)4] + KCl =>
2 FeCl2 + Cl2 + 8 KOH = 2 K[Fe(OH)4] + 6 KCl

NH4VO3 + H2SO4 + Zn = VO + (NH4)2SO4 + H2O + ZnSO4 =>
2 NH4VO3 + 4 H2SO4 + 3 Zn = 2 VO + (NH4)2SO4 + 4 H2O + 3 ZnSO4

CrBr3 + NaNO3 = Cr(NO3)3 + NaBr =>
CrBr3 + 3 NaNO3 = Cr(NO3)3 + 3 NaBr

Ca(OH)2 + H3PO4 = Ca3(PO4)2 + OHH =>
3 Ca(OH)2 + 2 H3PO4 = Ca3(PO4)2 + 6 OHH

NH4OH + I = NH4I + OH =>
NH4OH + I = NH4I + OH

KClO4 + FeSO4 + H2SO4 = KCl + Fe2(SO4)3 + H2O =>
KClO4 + 8 FeSO4 + 4 H2SO4 = KCl + 4 Fe2(SO4)3 + 4 H2O

Fe(OH) + HF = HOH + FeF =>
Fe(OH) + HF = HOH + FeF

Zn + (OH)2 = Zn(OH)2 =>
Zn + (OH)2 = Zn(OH)2

Al2(SO4)3 + NH3 + H2O = Al(OH)3 + (NH4)2SO4 =>
Al2(SO4)3 + 6 NH3 + 6 H2O = 2 Al(OH)3 + 3(NH4)2SO4

H2SO4 + NaNO2 + C3H8O = C3H7NO2 + H2O + Na2SO4 =>
H2SO4 + 2 NaNO2 + 2 C3H8O = 2 C3H7NO2 + 2 H2O + Na2SO4

KSCN + K2CrO4 = CrO4 + K2KSCN =>
KSCN + K2CrO4 = CrO4 + K2KSCN

Al + H2Co3 = Al2(Co3)2 + H2 =>
2 Al + 2 H2Co3 = Al2(Co3)2 + 2 H2

NH4{+} + BiO3{-} = NH4BiO3 =>
NH4{+} + BiO3{-} = NH4BiO3

Al + H2PO4 = AlPO4 + H2 =>
Al + H2PO4 = AlPO4 + H2

C6H5COCH3 + NaBH4 + H2O = C6H5CHOHCH3 + NaBO4H4 =>
4 C6H5COCH3 + NaBH4 + 4 H2O = 4 C6H5CHOHCH3 + NaBO4H4

H3PO3 + N2H4 = H3PO2 + N2 + H2O =>
2 H3PO3 + N2H4 = 2 H3PO2 + N2 + 2 H2O

KOHH3PO4 = KOH + H3PO4 =>
KOHH3PO4 = KOH + H3PO4

Na3H2IO6 + Ba(NO3)2 = Ba3H4I2O12 + NaNO3 =>
2 Na3H2IO6 + 3 Ba(NO3)2 = Ba3H4I2O12 + 6 NaNO3

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Balance the equation of any chemical reaction
 Equations balanced on the previous day Equations balanced on the next day
Equations balanced on 12/13/24
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Equations balanced on 12/20/23
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