Printed from https://www.webqc.org

Chemical Equations Balanced on 11/15/24

 Equations balanced on the previous day Equations balanced on the next day
Balance the equation of any chemical reaction
KI + K2Cr2O7 + H2O = Cr2O3 + KOH + I2 =>
6 KI + K2Cr2O7 + 4 H2O = Cr2O3 + 8 KOH + 3 I2

Br2 + KF = F2 + KBr =>
Br2 + 2 KF = F2 + 2 KBr

HCl + NaOH = NaCl + H2O =>
HCl + NaOH = NaCl + H2O

CaCO3(s) + CH3COOH(aq) = Ca(CH3COO)2 + H2O + CO2 =>
CaCO3(s) + 2 CH3COOH(aq) = Ca(CH3COO)2 + H2O + CO2

KO2 + H2O + CO2 = KHCO3 + O2 = NAHCO3 + CO2 + NA2CO3 + H2O =>
4 KO2 + 2 H2O + 4 CO2 = 4 KHCO3 + 3 O2

C3H8 + O2 = CO2 + H2O =>
C3H8 + 5 O2 = 3 CO2 + 4 H2O

P + O2 = P2O5 =>
4 P + 5 O2 = 2 P2O5

KMnO4 + H2O + C2H6 = C3H8O2 + MnO2 + KOH =>
10 KMnO4 + 2 H2O + 9 C2H6 = 6 C3H8O2 + 10 MnO2 + 10 KOH

N2 + H2 = NH3 =>
N2 + 3 H2 = 2 NH3

Fe + CuNO3 = Cu + Fe(NO3)2 =>
Fe + 2 CuNO3 = 2 Cu + Fe(NO3)2

Rb + S8 = Rb2S =>
16 Rb + S8 = 8 Rb2S

NaOH + H2CO3 = Na2CO3 + H2O =>
2 NaOH + H2CO3 = Na2CO3 + 2 H2O

HCl + NaOH = NaCl + H2O =>
HCl + NaOH = NaCl + H2O

KC8H5O4 + O2 = CO2 + H2O + KHCO3 =>
2 KC8H5O4 + 15 O2 = 14 CO2 + 4 H2O + 2 KHCO3

HCl + CaCO3 = CaCl2 + H2O + CO2 =>
2 HCl + CaCO3 = CaCl2 + H2O + CO2

C24H42O21 + H2O = C6H12O6 =>
C24H42O21 + 3 H2O = 4 C6H12O6

Cr2O7{-2} + H{+} + SO2{-2} = SO4{-2} + H2O + Cr{+3} =>
2 Cr2O7{-2} + 16 H{+} + 3 SO2{-2} = 3 SO4{-2} + 8 H2O + 4 Cr{+3}

Na2O + H2O = NaOH =>
Na2O + H2O = 2 NaOH

SbH3 + KMnO4 + H2SO4 = H3SbO4 + MnSO4 + K2SO4 + H2O =>
5 SbH3 + 8 KMnO4 + 12 H2SO4 = 5 H3SbO4 + 8 MnSO4 + 4 K2SO4 + 12 H2O

F2O7 + HCl = FCl7 + H2O =>
F2O7 + 14 HCl = 2 FCl7 + 7 H2O

N2 + H2 = NH3 =>
N2 + 3 H2 = 2 NH3

CH4 + Br2 = CH3Br + HBr =>
CH4 + Br2 = CH3Br + HBr

C + I = CI2 =>
C + 2 I = CI2

HgO(s) = Hg(l) + O2(g) =>
2 HgO(s) = 2 Hg(l) + O2(g)

NH4OH + C2O4H2 = (NH4)2C2O4 + H2O =>
2 NH4OH + C2O4H2 = (NH4)2C2O4 + 2 H2O

Na + H2O = NaOH + H2 =>
2 Na + 2 H2O = 2 NaOH + H2

Na2B4O7 + HCl + H2O = H3BO3 + NaCl =>
Na2B4O7 + 2 HCl + 5 H2O = 4 H3BO3 + 2 NaCl

PbSO4 = PbSO3 + O2 =>
2 PbSO4 = 2 PbSO3 + O2

Ca + O2 = CaO =>
2 Ca + O2 = 2 CaO

KClO3 = KCl + O2 =>
2 KClO3 = 2 KCl + 3 O2

CH3CO2H(aq) + NaOH(aq) = CH3CO2Na(aq) + H2O(l) =>
CH3CO2H(aq) + NaOH(aq) = CH3CO2Na(aq) + H2O(l)

H2MnO4 = HMnO4 + MnO2 + H2O =>
3 H2MnO4 = 2 HMnO4 + MnO2 + 2 H2O

C5H6O(g) + O2(g) = CO2(g) + H2O(g) =>
C5H6O(g) + 6 O2(g) = 5 CO2(g) + 3 H2O(g)

Al + ZnCl2 = Zn + AlCl3 =>
2 Al + 3 ZnCl2 = 3 Zn + 2 AlCl3

Ca(ClO4)2(aq) = Ca(s) + ClO4(aq) =>
Ca(ClO4)2(aq) = Ca(s) + 2 ClO4(aq)

RbNO3 + BeF2 = Be(NO3)2 + RbF =>
2 RbNO3 + BeF2 = Be(NO3)2 + 2 RbF

PbSO4 = PbSO3 + O2 =>
2 PbSO4 = 2 PbSO3 + O2

Ca(ClO)2 + HI = CaCl2 + I2 + H2O =>
Ca(ClO)2 + 4 HI = CaCl2 + 2 I2 + 2 H2O

K3PO4 + NH3 = NH3PO4 + K =>
K3PO4 + NH3 = NH3PO4 + 3 K

KCl + MnO2 + KHSO4 = K2SO4 + MnHSO4 + H2O + Cl2 =>
6 KCl + 2 MnO2 + 10 KHSO4 = 8 K2SO4 + 2 MnHSO4 + 4 H2O + 3 Cl2

Br2 + Na2CO3 = NaBr + NaBrO3 + CO2 =>
3 Br2 + 3 Na2CO3 = 5 NaBr + NaBrO3 + 3 CO2

KBr + H2SO4 = K2SO4 + HBr =>
2 KBr + H2SO4 = K2SO4 + 2 HBr

CH3(CH2)7CH3 + O2 = CO2 + H2O =>
CH3(CH2)7CH3 + 14 O2 = 9 CO2 + 10 H2O

C6H11CH2CH3 + O2 = CO2 + H2O =>
C6H11CH2CH3 + 12 O2 = 8 CO2 + 8 H2O

Al + CuCl = Al2Cu3 + Cl =>
2 Al + 3 CuCl = Al2Cu3 + 3 Cl

Na2[Zn(OH)4] + H2SO4 = ZnSO4 + Na2SO4 + H2O =>
Na2[Zn(OH)4] + 2 H2SO4 = ZnSO4 + Na2SO4 + 4 H2O

Fe + (SO4)3 + KOH = K2SO4 + Fe(OH)3 =>
2 Fe + (SO4)3 + 6 KOH = 3 K2SO4 + 2 Fe(OH)3

Si + Br2 = Si8Br4 =>
8 Si + 2 Br2 = Si8Br4

NaOHNH4CO3 = NaCO3NH3H2O =>
NaOHNH4CO3 = NaCO3NH3H2O

Pb(NO3)2 + KI = PbI2 + KNO3 =>
Pb(NO3)2 + 2 KI = PbI2 + 2 KNO3

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60
Balance the equation of any chemical reaction
 Equations balanced on the previous day Equations balanced on the next day
Equations balanced on 11/08/24
Equations balanced on 10/16/24
Equations balanced on 11/15/23
Please let us know how we can improve this web app.
Menu Balance Molar mass Gas laws Units Chemistry tools Periodic table Chemical forum Symmetry Constants Contribute Contact us
How to cite?