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Chemical Equations Balanced on 08/10/24

 Equations balanced on the previous day Equations balanced on the next day
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Ti + NaClO + KOH = K2TiO3 + NaCl + H2O =>
Ti + 2 NaClO + 2 KOH = K2TiO3 + 2 NaCl + H2O

MgCO3(s) + H3O(aq) = H2O(l) + Mg2(aq) + H2CO3(aq) =>
2 MgCO3(s) + 4 H3O(aq) = 4 H2O(l) + Mg2(aq) + 2 H2CO3(aq)

KCl + NH4Br = KBr + ClNH4 =>
KCl + NH4Br = KBr + ClNH4

KH2PO4 + Ba(NO3)2 = Ba3(PO4)2 + KNO3 + HNO3 =>
2 KH2PO4 + 3 Ba(NO3)2 = Ba3(PO4)2 + 2 KNO3 + 4 HNO3

TiBr4 + H2O = TiO2H2O + HBr =>
TiBr4 + 3 H2O = TiO2H2O + 4 HBr

Au{3+} + NH4{+} = Au + N2H5{+} + H{+} =>
2 Au{3+} + 6 NH4{+} = 2 Au + 3 N2H5{+} + 9 H{+}

Al + ClO2 = Al(ClO2)3 =>
Al + 3 ClO2 = Al(ClO2)3

AgF + H2O = Ag + HF + O2 =>
4 AgF + 2 H2O = 4 Ag + 4 HF + O2

(NH4)2SO3 + HCl = ClNH4 + H2SO3 =>
(NH4)2SO3 + 2 HCl = 2 ClNH4 + H2SO3

Fe2(C2O4)3 + Na3PO4 = FePO4 + Na2C2O4 =>
Fe2(C2O4)3 + 2 Na3PO4 = 2 FePO4 + 3 Na2C2O4

C6H5(OH)2 + NaOH = C6H5(ONa)2 + H2O =>
C6H5(OH)2 + 2 NaOH = C6H5(ONa)2 + 2 H2O

H2CO3(aq) + Sr(OH)2(aq) = H2O + Sr(HCO3)2(aq) =>
2 H2CO3(aq) + Sr(OH)2(aq) = 2 H2O + Sr(HCO3)2(aq)

Al2(SO4)3(aq) + K2SO4(aq) + H2O = KAl(SO4)2*12H2O =>
Al2(SO4)3(aq) + K2SO4(aq) + 24 H2O = 2 KAl(SO4)2*12H2O

CuOH + HMnO4 = Cu(MnO4) + H2O =>
CuOH + HMnO4 = Cu(MnO4) + H2O

H2O(l) + Cl(g) = HCl(aq) + O(g) =>
H2O(l) + 2 Cl(g) = 2 HCl(aq) + O(g)

Al2O3 + FeS = Al + FeSO4 =>
4 Al2O3 + 3 FeS = 8 Al + 3 FeSO4

C8H10 + H2O2 = CO2 + H2O =>
C8H10 + 21 H2O2 = 8 CO2 + 26 H2O

C4H10 + K2Cr2O7 + H2SO4 = C8H6O4 + K2SO4 + CrSO4 + H2O =>
8 C4H10 + 11 K2Cr2O7 + 33 H2SO4 = 4 C8H6O4 + 11 K2SO4 + 22 CrSO4 + 61 H2O

Cu(C6H12N4)(ClO4)2 + Cu(NH3)4(ClO4)2 = CuO + Cl2 + N2 + H2O + CO =>
Cu(C6H12N4)(ClO4)2 + 5 Cu(NH3)4(ClO4)2 = 6 CuO + 6 Cl2 + 12 N2 + 36 H2O + 6 CO

NaOCl + Na2S2O3 + NaOH = NaCl + Na2SO4 + H2O =>
4 NaOCl + Na2S2O3 + 2 NaOH = 4 NaCl + 2 Na2SO4 + H2O

C3H8 + KMnO4 + H2SO4 = C3H6O + MnSO4 + K2SO4 + H2O =>
5 C3H8 + 4 KMnO4 + 6 H2SO4 = 5 C3H6O + 4 MnSO4 + 2 K2SO4 + 11 H2O

Ca(OH)2 + H(C1O4) = Ca(C1O4) + H(OH)2 =>
Ca(OH)2 + H(C1O4) = Ca(C1O4) + H(OH)2

S2O3{2-} + OCl{-} = Cl{-} + S2O5{2-} =>
S2O3{2-} + 2 OCl{-} = 2 Cl{-} + S2O5{2-}

MgO + Na2SiO3 = MgSiO3 + Na + O2 =>
2 MgO + 2 Na2SiO3 = 2 MgSiO3 + 4 Na + O2

Cu2O + S = Cu2S + SO2 =>
2 Cu2O + 3 S = 2 Cu2S + SO2

NaCl + Fe(OH)3 + HCl = FeCl2 + NaClO + H2O =>
NaCl + 2 Fe(OH)3 + 4 HCl = 2 FeCl2 + NaClO + 5 H2O

CaCo2 + AgNO3 = CaNO3 + AgCo2 =>
CaCo2 + AgNO3 = CaNO3 + AgCo2

CUSO4 + KI = CUI + KI3 + K2SO4 =>
2 CUSO4 + 5 KI = 2 CUI + KI3 + 2 K2SO4

Pb(C2H3O2)2 + Fe(NO3)3 = Fe(C2H3O2)3 + Pb(NO3)2 =>
3 Pb(C2H3O2)2 + 2 Fe(NO3)3 = 2 Fe(C2H3O2)3 + 3 Pb(NO3)2

NaOH + H2(SO)4 = Na2(SO)4 + H2O =>
2 NaOH + H2(SO)4 = Na2(SO)4 + 2 H2O

(NH4)2C2O4 + CaCl2 = CaC2O4 + NH4Cl =>
(NH4)2C2O4 + CaCl2 = CaC2O4 + 2 NH4Cl

CuCl + KOH = Cu2O + KCl + H2O =>
2 CuCl + 2 KOH = Cu2O + 2 KCl + H2O

C4H9OH + KMnO4 + H2SO4 = C3H7COH + MnSO4 + K2SO4 + H2O =>
5 C4H9OH + 2 KMnO4 + 3 H2SO4 = 5 C3H7COH + 2 MnSO4 + K2SO4 + 8 H2O

FeS2 + NaOH = Fe2O3 + Na2S + Na2S2O3 + H2O =>
8 FeS2 + 30 NaOH = 4 Fe2O3 + 14 Na2S + Na2S2O3 + 15 H2O

CuSO4*5H2O + C2H2O4*2H2O = CuC2O4 + H2SO4 + H2O =>
CuSO4*5H2O + C2H2O4*2H2O = CuC2O4 + H2SO4 + 7 H2O

H2SO3 + NaH2 = NaSO + H2O =>
H2SO3 + NaH2 = NaSO + 2 H2O

CrO4{-2} + H{+} = H2CrO4 =>
CrO4{-2} + 2 H{+} = H2CrO4

AsCl3 + C2H2 = ClC2H2AsCl2 =>
AsCl3 + C2H2 = ClC2H2AsCl2

HS + OH = SO4 + H2O =>
HS + 9 OH = SO4 + 5 H2O

Na2S + Fe(NO3)3 = FeS + Na2(NO3)3 =>
Na2S + Fe(NO3)3 = FeS + Na2(NO3)3

CO2 + HO = HCO3 =>
CO2 + HO = HCO3

CO2 + KNO3 = KCO3 + NO2 =>
CO2 + KNO3 = KCO3 + NO2

B{3+} + F{-} = BF3 =>
B{3+} + 3 F{-} = BF3

Mn + LiI = Li2 + MnI3 =>
2 Mn + 6 LiI = 3 Li2 + 2 MnI3

SnCl2 + KNO2 + HCl = SnCl4 + N2O + KCl + H2O =>
2 SnCl2 + 2 KNO2 + 6 HCl = 2 SnCl4 + N2O + 2 KCl + 3 H2O

CH3CH2CH2CH2OH + KMnO4 + H2SO4 = CH3CH2CH2COOH + KHSO4 + MnSO4 + H2O =>
5 CH3CH2CH2CH2OH + 4 KMnO4 + 8 H2SO4 = 5 CH3CH2CH2COOH + 4 KHSO4 + 4 MnSO4 + 11 H2O

NaOH + H2[SiF6] = Na2[SiF6] + H2O =>
2 NaOH + H2[SiF6] = Na2[SiF6] + 2 H2O

FeCO3 + H2S = FeS + H2O + CO2 =>
FeCO3 + H2S = FeS + H2O + CO2

Cu + AgNo3 = Cu3(No3)2 + Ag =>
3 Cu + 2 AgNo3 = Cu3(No3)2 + 2 Ag

TiCl4 + Ti3Al = TiCl2 + AlCl3 =>
9 TiCl4 + 2 Ti3Al = 15 TiCl2 + 2 AlCl3

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Balance the equation of any chemical reaction
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